A 25-turn ideal solenoid has an inductance of (4.19x10^-3) H. To generate an EMF of (1.5x10^0) V what should be the rate of change of the current? Express your result as the magnitude in A/s.
Q: In the circuit shown in (Figure 1), E = 56.0 V, R₁ = 36.0 , R₂ = 22.0 , and L= 0.290 H. Part A…
A: Givenε=56 VR1=36 ΩR2=22 ΩL=0.290 H
Q: A 10-turn ideal solenoid has an inductance of (3.9x10^-3) H. To generate an EMF of (1.16x10^0) V…
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Q: Two coils, held in fixed positions, have a mutual inductance of 100 μH. What is the peak emf in one…
A: Inductors are passive electric devices capable of storing energy in them as magnetic fields. When…
Q: A solenoid with 445 turns has a length of 8.00 cm and a cross-sectional area of 2.50 x 109 m². Find…
A: Given data: Number of turns (N) = 445 Length = 8.00 cm = 8.00×10-2 m Cross sectional area (A) =…
Q: A solenoid with 455 turns has a length of 8.00 cm and a cross-sectional area of 2.90 ✕ 10−9 m2. Find…
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Q: A 20.0 V emf is applied to a coil with an inductance of 40.0 mH and a resistance of 0.500 Ω. a)…
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Q: Say that a large research solenoid has a self-inductance of L = 1.5 Henry (H). a. You observe a…
A: The objective of this question is to calculate the electromotive force (emf) that was set up by the…
Q: A coiled telephone cord forms a spiral with 90.0 turns, a diameter of 1.30 cm, and an unstretched…
A: Given that,Nymber of turns (N) = 90Diameter of coiled telephone (D) = 1.30 cmRadius of of coiled…
Q: A 521-turn solenoid has a radius of 7.00 mm and an overall length of 15.0 cm. (a) What is its…
A: Given: No. of Turns (N) = 521 Radius (r) = 7 mm = 0.007 m; Length (l) = 15 cm = 0.15 m
Q: A coiled telephone cord forms a spiral with 60.0 turns, a diameter of 1.30 cm, and an unstretched…
A: Write the expression for the inductance of the solenoid.
Q: A solenoid with 485 turns has a length of 5.00 cm and a cross-sectional area of 2.90 ✕ 10−9 m2. Find…
A: Lenz's law says that induced current in a loop is due to the change in magnetic field in the loop…
Q: A solenoid with 425 turns has a length of 5.50 cm and a cross-sectional area of 2.60 ✕ 10−9 m2. Find…
A: Given quantities: Number of turns (N) = 425 Length of the solenoid (d) = 5.50 cm Area of…
Q: A solenoid of radius 2.70 cm has 580 turns and a length of 25.0 cm. (a) Find its inductance. mH (b)…
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Q: How many turns are necessary to produce an inductance of 3 mH in a coil of radius 3 cm and length 7…
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Q: A solenoid of radius 2.70 cm has 680 turns and a length of 25.0 cm. (a) Find its inductance. mH (b)…
A: Required Inductance of solenoid. Rate of current to produce an emf of 60 mV
Q: A solenoid of radius 2.70 cm has 580 turns and a length of 15.0 cm. (a) Find its inductance. mH (b)…
A: Given radius of solenoid(r)=0.027 m so cross section arey(A)=0.00229 m2 turns(N)=580 length(l)=0.15…
Q: A solenoid of radius 3.50 cm has 800 turns and a length of 25.0 cm. (a) Find its inductance. mH (b)…
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Q: inductance
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Q: A solenoid of radius 2.50 cm has 400 turns and a length of 20.0 cm. Find its inductance
A: We have given Radius r = 2.50 cm r = 2.50 × 10-2m Number of turns N = 400 Length of…
Q: The current through inductance L is given by I = Io e-t/T. Express your answer in terms of some,…
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Q: A solenoid with 495 turns has a length of 8.00 cm and a cross-sectional area of 3.20 ✕ 10−9 m2. Find…
A: Required : (a)the solenoid's inductance (in H)H(b)the average emf around the solenoid (in V)V
Q: Figure QB2b shows the set-up for a simple DC motor. The plane loop of wire, ABCD where AC = BD = 25…
A: The entire length of the wire in the plane loop (L) = 22×AB+BD=2×50cm+25 cm=2×75 cm=2×0.75 m =1.5 m…
Q: A solenoid (length = 16.7 cm, radius = 1.3 cm) has a self inductance of 0.004 H. How many loops of…
A: Given that length of the solenoid is l=16.7 cm⇒l=16.7×10-2 m Radius is r=1.3 cm⇒r=1.3×10-2 m Area…
Q: A conducting coil, with current i(t) = 5.40e -0.0250 sin(120mt), withi in amperes and t in seconds,…
A: The emf induced in a coil 2 due to a current carrying coil 1 is given by the formula, ε=-Mdidt…
Q: A solenoid (length = 20.2 cm, radius = 3.1 cm) has a self inductance of 0.005 H. How many loops of…
A: Here we have to use basic formula.
Q: A solenoid with 515 turns has a length of 5.50 cm and a cross-sectional area of 2.60 ✕ 10−9 m2. Find…
A: (a) The formula to calculate the inductance (L) is as follows: L=μ0N2Ad Thus, the inductance is,…
Q: A solenoid of radius 3.10 cm has 440 turns and a length of 15.0 cm. (a) Find its inductance. mH (b)…
A: Step 1:Step 2:
Q: An electromagnet can be modeled as an inductor in series with a resistor. Consider a large…
A: Resistance (R) = 6 ΩInductance (L) = 10 HEmf of the battery (E) = 24 V
Q: A solenoid of radius 5 cm has 428 turns and a length of 38 cm. (a) Find its inductance. μ 0 = 4 π…
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Q: An electric current flows through a coil with an inductance of 15.3 mH. The graph shows the…
A: Given Inductance L = 15.3 mH = 15.3 × 10-3 H Time period of current T = 20 ms = 20 × 10-3 s Peak…
Q: A solenoid of radius 1.50 cm has 600 turns and a length of 25.0 cm. (a) Find its inductance. mH (b)…
A: To calculate the inductance of a solenoid, we can use the formula for the inductance of a solenoid:
Q: A solenoid of radius 3.50 cm has 520 turns and a length of 25.0 cm. Find its inductance and the…
A: Radius, r = 3.50 cm = 0.035 m Number of turns, n = 520 Length, l = 25.0 cm = 0.25 m Emf, ε = 0 mV
Q: An alternating current generator in the United Kingdom generates current with a frequency of 50 Hz.…
A: Given quantities : Frequency (v) = 50 Hz Let, the amplitude of the current be denoted as 'A' , the…
Q: A solenoid of radius 3.5 cm has 500 turns and a length of 25 cm. (A)Find its inductance. ?mH (b)…
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Q: solenoid with 525 turns has a length of 5.50 cm and a cross-sectional area of 3.00 ✕ 10−9 m2. Find…
A: number of turns = N = 525 length = l = 5.5 cm area = A = 3 X 10-9 m2
Q: A solenoid of radius 3.10 cm has 680 turns and a length of 25.0 cm. (a) Find its inductance. mH (b)…
A: Write the given values with the suitable variables. r=3.10 cm=3.10×10-2 mN=680L=25 cm=0.25 m Here,…
Q: A solenoid of radius 4 cm has 250 turns and a length of 20.0 cm. Find its inductance
A: When AC current passes through an inductor the magnetic field created will induce an emf inside the…
Q: A loop of wire has a self-inductance of 5.5 mH. You pass a current of 9.0 Amps though the loop, and…
A: Given Self- Inductance of loop ( L) = 5.5 mH = 5.5 × 10-3 H…
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- In the figure, R = 11.0 Ω, C = 6.82 μF, and L = 54.0 mH, and the ideal battery has emf = 32.0 V. The switch is kept in position a for a long time and then thrown to position b. What are the (a) frequency and (b) current amplitude of the resulting oscillations?A solenoid with 485 turns has a length of 5.50 cm and a cross-sectional area of 3.20 ✕ 10−9 m2. Find the solenoid's inductance and the average emf around the solenoid if the current changes from +3.50 A to −3.50 A in 5.33 ✕ 10−3 s (a) the solenoid's inductance (in H) ____ H (b) the average emf around the solenoid (in V) ____VAn electric current contains a battery that produces a voltage of 60 voltsV , a resistor with a resistance of 13 ohms, and inductor with an inductance of 5 henrys H . Using calculus, it can be shown that I I t (in amperes, A), when t seconds after the switch is closed is 13 5 60 1 13 t I e 1.4.1 Use this equation to express the time t as function of the currentI
- A solenoid with 455 turns has a length of 5.50 cm and a cross-sectional area of 3.50 ✕ 10−9 m2. Find the solenoid's inductance and the average emf around the solenoid if the current changes from +3.00 A to −3.00 A in 6.33 ✕ 10−3 s. (a) the solenoid's inductance (in H) (b) the average emf around the solenoid (in V)Apply error propagation to determine the associated uncertainty in the average volume… PlzA solenoid of radius 2.30 cm has 560 turns and a length of 25.0 cm. (a) Find its inductance. mH (b) Find the rate at which current must change through it to produce an emf of 50.0 mV. (Enter the magnitude.) A/s
- A solenoid with 495 turns has a length of 5.00 cm and a cross-sectional area of 2.90 ✕ 10−9 m2. Find the solenoid's inductance and the average emf around the solenoid if the current changes from +3.50 A to −3.50 A in 6.33 ✕ 10−3 s. (a) the solenoid's inductance (in H) H (b) the average emf around the solenoid (in V) VA solenoid with 505 turns has a length of 6.50 cm and a cross-sectional area of 2.50 ✕ 10−9 m2. Find the solenoid's inductance and the average emf around the solenoid if the current changes from +3.50 A to −3.50 A in 7.33 ✕ 10−3 s. (a) the solenoid's inductance (in H) _______ H (b)the average emf around the solenoid (in V) _______VTwo solenoids, A and B, are wound using equal lengths of the same kind of wire. The length of the axis of each solenoid is large compared with its diameter. The axial length of A is thrice as large as that of B, and A has twice as many turns as B. What is the ratio of the inductance of solenoid A to that of solenoid B?
- Two solenoids A and B, spaced close to each other and sharing the same cylindrical axis, have 390 and 590 turns, respectively. A current of 3.80 A in solenoid A produces an average flux of 300 μWb through each turn of A and a flux of 90.0 μWb through each turn of B. (a) Calculate the mutual inductance of the two solenoids. mH (b) What is the inductance of A? mH (c) What is the magnitude of the emf that is induced in B when the current in A changes at the rate of 0.500 A/s? mVI'm working on some homework and am stumped with this problem. Help would be great, thanks!A solenoid with 455 turns has a length of 8.00 cm and a cross-sectional area of 2.70 ✕ 10−9 m2. Find the solenoid's inductance and the average emf around the solenoid if the current changes from +4.00 A to −4.00 A in 6.83 ✕ 10−3 s. (a) the solenoid's inductance (in H) (b) the average emf around the solenoid (in V)