A solenoid with 505 turns has a length of 6.50 cm and a cross-sectional area of 2.50 ✕ 10−9 m2. Find the solenoid's inductance and the average emf around the solenoid if the current changes from +3.50 A to −3.50 A in 7.33 ✕ 10−3 s. (a) the solenoid's inductance (in H)  _______ H (b)the average emf around the solenoid (in V)  _______V

Q: A solenoid with 485 turns has a length of 7.00 cm and a cross-sectional area of 3.50 x 10-9 m2. Find…

A: a) The inductance of the solenoid can be obtained as L=μ∘N2AlSubstituting the given values :L=(4π x…

Q: A solenoid with 515 turns has a length of 5.00 cm and a cross-sectional area of 3.10 x 10-9 m². Find…

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Q: A circuit is constructed with four resistors, one inductor, one battery and a switch as shown. The…

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Q: A solenoid with 455 turns has a length of 8.00 cm and a cross-sectional area of 2.90 ✕ 10−9 m2. Find…

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Q: the solenoid's inductance (in H)   H (b) the average emf around the solenoid (in V)

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Q: A solenoid with 435 turns has a length of 7.00 cm and a cross-sectional area of 3.10 x 10-9 m². Find…

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Q: Self-inductance (L) of a 40.0 cm long solenoid containing N = 400 turns, and cross- sectional area…

A: Solution:-Given thatLength of solenoid (l)=40 cm=0.4 mNumber of turns (N)=400Cross sectional area…

Q: A solenoid with 435 turns has a length of 5.50 cm and a cross-sectional area of 2.60 ✕ 10−9 m2. Find…

A: Given value--- number of turns = 435. Length = 5.5 cm. Area = 2.6 × 10-9 m2 . change in current = 4…

Q: A 521-turn solenoid has a radius of 7.00 mm and an overall length of 15.0 cm. (a) What is its…

A: Given: No. of Turns (N) = 521 Radius (r) = 7 mm = 0.007 m; Length (l) = 15 cm = 0.15 m

Q: A solenoid with 485 turns has a length of 5.00 cm and a cross-sectional area of 2.90 ✕ 10−9 m2. Find…

A: Lenz's law says that induced current in a loop is due to the change in magnetic field in the loop…

Q: A solenoid with 485 turns has a length of 5.00 cm and a cross- sectional area of 3.00 X 10-⁹ m².…

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Q: A solenoid with 425 turns has a length of 5.50 cm and a cross-sectional area of 2.60 ✕ 10−9 m2. Find…

A: Given quantities: Number of turns (N) = 425 Length of the solenoid (d) = 5.50 cm Area of…

Q: A solenoid of radius 2.70 cm has 580 turns and a length of 25.0 cm. (a) Find its inductance. mH (b)…

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Q: A solenoid having an inductance of 5.00 µH is connected in series with a 1.17 k resistor. (a) If a…

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Q: solenoid with inductance L = 6.30 μΗ is connected in series with a resistor R 1.20 kO. At time t 0,…

A: (a)Current is given by,

Q: A solenoid of radius 2.70 cm has 680 turns and a length of 25.0 cm. (a) Find its inductance. mH (b)…

A: Required Inductance of solenoid. Rate of current to produce an emf of 60 mV

Q: A solenoid of radius 2.70 cm has 580 turns and a length of 15.0 cm. (a) Find its inductance. mH (b)…

A: Given  radius of solenoid(r)=0.027 m so cross section arey(A)=0.00229 m2 turns(N)=580 length(l)=0.15…

Q: A solenoid with 435 turns has a length of 5.00 cm and a cross-sectional area of 3.10 x 109 m². Find…

A: Given value--- number of turns = 425 . length = 5 cm. Area = 3.10 × 10-9 m2 . current changes from…

Q: R switch In the circuit shown in the figure above a battery supplies a constant voltage of E=30V,…

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Q: A solenoid of radius 3.50 cm has 800 turns and a length of 25.0 cm. (a) Find its inductance. mH (b)…

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Q: A solenoid with 495 turns has a length of 8.00 cm and a cross-sectional area of 3.20 ✕ 10−9 m2. Find…

A: Required :  (a)the solenoid's inductance (in H)H(b)the average emf around the solenoid (in V)V

Q: A solenoid (length = 16.7 cm, radius = 1.3 cm) has a self inductance of 0.004 H. How many loops of…

A: Given that  length of the solenoid is  l=16.7 cm⇒l=16.7×10-2 m Radius is  r=1.3 cm⇒r=1.3×10-2 m Area…

Q: A solenoid having an inductance of 9.20 µH is connected in series with a 1.52 k resistor. (a) If a…

A: Given Data: Inductance L =9.20μH Resistance R = 1.52kΩ Voltage in the circuit V= 16.0V Time t =…

Q: an inductor carrying a 1.45 A current stores an energy of 0.250 mJ, what is its inductance? ______mH…

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Q: A solenoid (length = 20.2 cm, radius = 3.1 cm) has a self inductance of 0.005 H. How many loops of…

A: Here we have to use basic formula.

Q: A solenoid of radius 3.10 cm has 440 turns and a length of 15.0 cm. (a) Find its inductance. mH (b)…

A: Step 1:Step 2:

Q: A solenoid of radius 5 cm has 428 turns and a length of 38 cm. (a)  Find its inductance.  μ 0 = 4 π…

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Q: A 524-turn solenoid has a radius of 8.65 mm and an overall length of 13.8 cm. (a) What is its…

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Q: A solenoid of radius 1.50 cm has 600 turns and a length of 25.0 cm. (a) Find its inductance. mH (b)…

A: To calculate the inductance of a solenoid, we can use the formula for the inductance of a solenoid:

Q: I need help answering this. Thank you! There is a solenoid with an inductance of 0.285 mH, a length…

A: Solution -

Q: In the circuit of Fig. 10.74, the current i, (t) = 8.132 cos 271 A. What is the inductance of L₁?…

A: Given,The current and voltage, The angular frequency, Resistance, Capacitance, The impedance of the…

Q: The current in the solenoid, whose inductance is L = 0.120 H, change in time according to the…

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Voltage Across Inductor

An actor is a passive electrical component that consists of a coil bent in the form of wire which uses electromagnetism to produce electric current through the coil. When the electric current flows through a conductor that is the coil, a magnetic flux is developed around the conductor. This flow of current through the coil creates a magnetic field based on Fleming's Right-hand thumb rule. If there is any decrease in the current passing through the inductor, then the magnetic field will also decrease and energy is released through the generation of electric current. There is also a secondary voltage inducing in the same coil due to the magnetic flux, since it opposes any changes in the electric current flowing through the circuit. An inductor is also called choke, coil, or solenoid. A choke is designed to block certain frequencies when the DC current passes. A winding coil is coated with insulation to give extra insulation and protect the circuit. They are usually tightly wrapped around a central core which is cylindrical in nature so that the magnetic flux can be induced. The solenoid is a three-dimension coil that is used to exhibit electromagnetism when the magnetic field is developed due to the current flowing through the coil. The sign convention of the inductor is the same as the power dissipating device. When the current flows into the positive side of the voltage across the inductor, the value is positive and the inductor dissipates power whereas when the inductor releases the power back to the circuit, the current has a negative sign convention.