A 10-turn ideal solenoid has an inductance of (3.9x10^-3) H. To generate an EMF of (1.16x10^0) V what should be the rate of change of the current? Express your result as the magnitude in A/s.
Q: A 10-turn ideal solenoid has an inductance of (3.9x10^-3) H. To generate an EMF of (1.16x10^0) V…
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A: Given: No. of Turns (N) = 521 Radius (r) = 7 mm = 0.007 m; Length (l) = 15 cm = 0.15 m
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Q: inductance
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Q: A solenoid of radius 2.50 cm has 400 turns and a length of 20.0 cm. Find its inductance
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A: To calculate the inductance of a solenoid, we can use the formula for the inductance of a solenoid:
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Q: A solenoid of radius 3.10 cm has 680 turns and a length of 25.0 cm. (a) Find its inductance. mH (b)…
A: Write the given values with the suitable variables. r=3.10 cm=3.10×10-2 mN=680L=25 cm=0.25 m Here,…
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- A toroidal solenoid with a rectangular cross-section is wound uniformly with 480 turns. The inner radius is a=5 cm, the outer radius is b=7.5 cm, and it has a thickness of t=1 cm. What is the self-inductance of this device?A solenoid of radius 4 cm has 250 turns and a length of 20.0 cm. Find its inductanceIn the figure, R = 11.0 Ω, C = 6.82 μF, and L = 54.0 mH, and the ideal battery has emf = 32.0 V. The switch is kept in position a for a long time and then thrown to position b. What are the (a) frequency and (b) current amplitude of the resulting oscillations?
- A solenoid with 505 turns has a length of 7.00 cm and a cross-sectional area of 3.10 ✕ 10−9 m2. Find the solenoid's inductance and the average emf around the solenoid if the current changes from +4.00 A to −4.00 A in 7.83 ✕ 10−3 s. (a) the solenoid's inductance (in H) (b) the average emf around the solenoid (in V)What's the self-inductance of a solenoid with 697 loops wrapped around a cylinder. The cylinder has a radius of 2.1 cm and a length of 21 cm?A solenoid with 455 turns has a length of 5.50 cm and a cross-sectional area of 3.50 ✕ 10−9 m2. Find the solenoid's inductance and the average emf around the solenoid if the current changes from +3.00 A to −3.00 A in 6.33 ✕ 10−3 s. (a) the solenoid's inductance (in H) (b) the average emf around the solenoid (in V)
- A rectangular conducting loop is placed on a flat surface, with the longer sides parallel to a current-carrying wire on the same surface, as shown in the figure. Assume h = 0.500 mm, w = 1.40 mm, and e = 2.50 mm. What is the mutual inductance (in pH) for this configuration? pHA solenoid with 505 turns has a length of 6.50 cm and a cross-sectional area of 2.50 ✕ 10−9 m2. Find the solenoid's inductance and the average emf around the solenoid if the current changes from +3.50 A to −3.50 A in 7.33 ✕ 10−3 s. (a) the solenoid's inductance (in H) _______ H (b)the average emf around the solenoid (in V) _______VTwo solenoids, A and B, are wound using equal lengths of the same kind of wire. The length of the axis of each solenoid is large compared with its diameter. The axial length of A is thrice as large as that of B, and A has twice as many turns as B. What is the ratio of the inductance of solenoid A to that of solenoid B?
- A 25-turn ideal solenoid has an inductance of (4.19x10^-3) H. To generate an EMF of (1.5x10^0) V what should be the rate of change of the current? Express your result as the magnitude in A/s.Two solenoids A and B, spaced close to each other and sharing the same cylindrical axis, have 390 and 590 turns, respectively. A current of 3.80 A in solenoid A produces an average flux of 300 μWb through each turn of A and a flux of 90.0 μWb through each turn of B. (a) Calculate the mutual inductance of the two solenoids. mH (b) What is the inductance of A? mH (c) What is the magnitude of the emf that is induced in B when the current in A changes at the rate of 0.500 A/s? mV