In the figure below, the conducting loop has fallen a short distance and is now falling at a constant velocity, vterminal. The loop has sides of length s=0.50 m, mass 30.0 g, and resistance R=1.00 Ω. If B=7.50 T and is directed into the page, answer the following question: Since the loop is moving at a constant velocity, there must be an equal force acting to hold the loop up. What current do you need to flow in the loop to produce this force? Also, use the induced EMF in this loop to determine terminal. Show all work and justify your answer.
In the figure below, the conducting loop has fallen a short distance and is now falling at a constant velocity, vterminal. The loop has sides of length s=0.50 m, mass 30.0 g, and resistance R=1.00 Ω. If B=7.50 T and is directed into the page, answer the following question: Since the loop is moving at a constant velocity, there must be an equal force acting to hold the loop up. What current do you need to flow in the loop to produce this force? Also, use the induced EMF in this loop to determine terminal. Show all work and justify your answer.
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In the figure below, the conducting loop has fallen a short distance and is now falling at a constant velocity, vterminal. The loop has sides of length s=0.50 m, mass 30.0 g, and resistance R=1.00 Ω. If B=7.50 T and is directed into the page, answer the following question:
Since the loop is moving at a constant velocity, there must be an equal force acting to hold the loop up. What current do you need to flow in the loop to produce this force? Also, use the induced EMF in this loop to determine terminal. Show all work and justify your answer.

Transcribed Image Text:Square loop of
copper wire-
ks = side length
X X X X x
x x xB xx
Above this line:
B uniform and horizontal
s = side
length
Below this line:
B = 0
wire diameter
d =
Oterminal = ?
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