A long, rectangular loop of width w, mass M, and resistanceRis at rest, with the plane of the loop parallel to the ground.Immediately to the left of the loop is a region of uniformmagnetic field B that points into the screen. At time í = 0, aconstant force F pushes the loop to the left, into the magneticfield region, as shown in the figure.Derive an expression for the speed v of the loop immediatelyafter it enters the magnetic field region in terms of the givenvariables and the time t.U =

Given, Width=w Mass=M Resistance=R Let the speed of the loop be v. Input power, P=Fv An induced emf…

Answered: A long, rectangular loop of width w,…

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Two coplanar and concentric circular loops of wire carry currents of I, = 5.90 A and I, = 2.30 A in opposite directions as in the figure below. Let r, = 12.0 cm and r, = 8.60 cm. (Assume the positive direction along the axis perpendicular to the faces of the loops is out of the screen (towards you) and assume the positive vertical direction is toward the top of the screen.) (a) What is the magnitude of the net magnetic field (in µT) at the center of the two loops? PT (b) What is the direction of the net magnetic field at the center of the two loops? out of the screen O into the screen O toward the top of the screen O toward the bottom of the screen (c) Let r, remain fixed at 12.0 cm and let r, be a variable. Determine the value ofr, (in cm) such that the net field at the center of the loops is zero. cm
You are evaluating the performance of a large electromagnet. The magnetic field of the electromagnet is zero at t = 0 and increases as the current through the windings of the electromagnet is increased. You determine the magnetic field as a function of time by measuring the time dependence of the current induced in a small coil that you insert between the poles of the electromagnet, with the plane of the coil parallel to the pole faces as for the loop in (Figure 1). The coil has 4 turns, a radius of 0.700 cm, and a resistance of 0.190. You measure the current i in the coil as a function of time t. Your results are shown in (Figure 2). Throughout your measurements, the current induced in the coil remains in the same direction. igure 1 of 2 S N ▼ Part A Calculate the magnetic field at the location of the coil for t = 2.00 s. Express your answer to three significant figures and include the appropriate units. μA ? B = Value Units Submit Request Answer Part B Calculate the magnetic field at…
A conducting bar of length ℓ moves to the right on two frictionless rails as shown in the figure below. A uniform magnetic field directed into the page has a magnitude of 0.330 T. Assume R = 8.70 Ω and ℓ = 0.390 m. A vertical bar and two parallel horizontal rails lie in the plane of the page, in a region of uniform magnetic field, vector Bin, pointing into the page. The parallel rails run from left to right, with one a distance ℓ above the other. The left ends of the rails are connected by a vertical wire containing a resistor R. The vertical bar lies across the rails to the right of the wire. The bar moves to the right with velocity vector v. (a) At what constant speed should the bar move to produce an 8.60-mA current in the resistor? m/s(b) What is the direction of the induced current? clockwisecounterclockwise into the pageout of the page (c) At what rate is energy delivered to the resistor? mW(d) Explain the origin of the energy being delivered to the resistor.
Let's add a battery to the usual sliding rod set-up: B is uniform sliding rod The whole circuit is lying horizontally on the ground. The rod starts at rest, and accelerates due to the magnetic force on it. After a while, you discover that its velocity stops changing. What is the value of the final speed (in m/s) of the rod? The magnetic field is 8.27T, the battery has an emf of 6.03V, the resistor is 4.54 ohm, and the distance between the two parallel rails is 4.56m. Hint: Pay attention to the magnitude of the magnetic force on the sliding rod. Rewrite the circuit in the usual way: by replacing the sliding rod with a battery of emf=BvL; then apply Kirchhoff's loop rule.
Two coplanar and concentric circular loops of wire carry currents of I1 = 5.60 A and I2 = 2.60 A in opposite directions as in the figure below. Let r1 = 12.0 cm and r2 = 8.50 cm. (Assume the positive direction along the axis perpendicular to the faces of the loops is out of the screen (towards you) and assume the positive vertical direction is toward the top of the screen.) (a)What is the magnitude of the net magnetic field (in µT) at the center of the two loops? µT (b)What is the direction of the net magnetic field at the center of the two loops? out of the screen into the screen toward the top of the screen toward the bottom of the screen (c)Let r1 remain fixed at 12.0 cm and let r2 be a variable. Determine the value of r2 (in cm) such that the net field at the center of the loops is zero.
Consider the arrangement shown in the figure below where R = 7.50 Ω, ℓ = 1.10 m, and B = 3.00 T. A vertical bar and two parallel horizontal rails lie in the plane of the page, in a region of uniform magnetic field, vector B, pointing into the page. The parallel rails run from left to right, with one a distance ℓ above the other. The left ends of the rails are connected by a vertical wire containing a resistor R. The vertical bar lies across the rails to the right of the wire. Force vector Fapp points from the bar toward the right. (a) At what constant speed (in m/s) should the bar be moved to produce a current of 2.00 A in the resistor? m/s (b) What power (in W) is delivered to the resistor? W (c) What magnetic force (in N) is exerted on the moving bar? (Enter the magnitude.) N (d) What instantaneous power (in W) is delivered by the force Fapp on the moving bar? W
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