sleep apnea. What can be concluded at the level of significance of a = 0.01? î a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? Select an answer (please enter a decimal) H₁: ? Ⓒ Select an answer (Please enter a decimal) c. The test statistic ? ↑ = (please show your answer to 3 decimal places.)

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**Hypothesis Test for Proportion of Sleep Apnea in Inner City Residents**

13% of all Americans suffer from sleep apnea. A researcher suspects that a higher percentage of those who live in the inner city have sleep apnea. Of the 321 people from the inner city surveyed, 51 of them suffered from sleep apnea. What can be concluded at the level of significance of α = 0.01?

a. **For this study, we should use:**
   - `Test Statistic` = z

b. **The null and alternative hypotheses would be:**
   - \( H_0 \): \( p \leq 0.13 \)
   - \( H_1 \): \( p > 0.13 \)

c. **The test statistic (z) =** 
   \[
   \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1 - p_0)}{n}}}
   \]
   \[
   \hat{p} = \frac{51}{321} \approx 0.159
   \]
   \[
   z = \frac{0.159 - 0.13}{\sqrt{\frac{0.13 \times (1 - 0.13)}{321}}} \approx 1.501
   \]

d. **The p-value =**
   \[
   0.0668
   \]

e. **The p-value is:**
   \[
   > \alpha
   \]

f. **Based on this, we should:**
   - Fail to reject the null hypothesis.

g. **Thus, the final conclusion is that:**
   - The data suggest the population proportion is not significantly larger than 13% at α = 0.01, so there is not sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is larger than 13%.

h. **Interpret the p-value in the context of the study:**
   - If the sample proportion of inner city residents who have sleep apnea is 16% and if another 321 inner city residents are surveyed then there would be a 6.2% chance of concluding that more than 13% of all inner city residents have sleep apnea.
Transcribed Image Text:**Hypothesis Test for Proportion of Sleep Apnea in Inner City Residents** 13% of all Americans suffer from sleep apnea. A researcher suspects that a higher percentage of those who live in the inner city have sleep apnea. Of the 321 people from the inner city surveyed, 51 of them suffered from sleep apnea. What can be concluded at the level of significance of α = 0.01? a. **For this study, we should use:** - `Test Statistic` = z b. **The null and alternative hypotheses would be:** - \( H_0 \): \( p \leq 0.13 \) - \( H_1 \): \( p > 0.13 \) c. **The test statistic (z) =** \[ \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1 - p_0)}{n}}} \] \[ \hat{p} = \frac{51}{321} \approx 0.159 \] \[ z = \frac{0.159 - 0.13}{\sqrt{\frac{0.13 \times (1 - 0.13)}{321}}} \approx 1.501 \] d. **The p-value =** \[ 0.0668 \] e. **The p-value is:** \[ > \alpha \] f. **Based on this, we should:** - Fail to reject the null hypothesis. g. **Thus, the final conclusion is that:** - The data suggest the population proportion is not significantly larger than 13% at α = 0.01, so there is not sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is larger than 13%. h. **Interpret the p-value in the context of the study:** - If the sample proportion of inner city residents who have sleep apnea is 16% and if another 321 inner city residents are surveyed then there would be a 6.2% chance of concluding that more than 13% of all inner city residents have sleep apnea.
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