image attatched ### h. Interpret the p-value in the context of the study.- ○ There is a 14% chance of a Type I error.- ○ If the population proportion of inner city residents who have sleep apnea is 14% and if another 369 inner city residents are surveyed, then there would be a 5.49% chance fewer than 11% of the 369 residents surveyed have sleep apnea.- ○ There is a 5.49% chance that fewer than 14% of all inner city residents have sleep apnea.- ○ If the sample proportion of inner city residents who have sleep apnea is 11% and if another 369 inner city residents are surveyed, then there would be a 5.49% chance of concluding that fewer than 14% of inner city residents have sleep apnea.### i. Interpret the level of significance in the context of the study.- ○ If the population proportion of inner city residents who have sleep apnea is smaller than 14% and if another 369 inner city residents are surveyed, then there would be a 5% chance that we would end up falsely concluding that the proportion of all inner city residents who have sleep apnea is equal to 14%.- ○ There is a 5% chance that aliens have secretly taken over the earth and have cleverly disguised themselves as the presidents of each of the countries on earth.- ○ There is a 5% chance that the proportion of all inner city residents who have sleep apnea is smaller than 14%.- ○ If the population proportion of inner city residents who have sleep apnea is 14% and if another 369 inner city residents are surveyed, then there would be a 5% chance that we would end up falsely concluding that the proportion of all inner city residents who have sleep apnea is smaller than 14%. **Investigation into Sleep Apnea Prevalence among Inner City Residents****Background:**14% of all Americans suffer from sleep apnea. A researcher suspects that a lower percentage of those who live in the inner city have sleep apnea. Out of 369 people from the inner city surveyed, 41 were found to suffer from sleep apnea. We seek to conclude at a significance level of α = 0.05.**Steps for Hypothesis Testing:**a. **Statistical Test Selection:** - Choose the appropriate statistical test for this study.b. **Formulate Hypotheses:** - **Null Hypothesis (\(H_0\))**: The population proportion is equal to the known value (0.14). - **Alternative Hypothesis (\(H_1\))**: The population proportion is less than the known value (0.14).c. **Calculate Test Statistic:** - Compute the test statistic and round to three decimal places.d. **Determine the p-value:** - Calculate the p-value and round to four decimal places.e. **Comparison with Significance Level:** - Compare the p-value to α to determine if it is less than or equal to α.f. **Decision Making:** - Decide whether to reject or not reject the null hypothesis.g. **Draw Conclusions:** - Based on the above steps, select the correct conclusion about the population proportion. 1. The data suggest the population proportion is not significantly smaller than 14% at α = 0.05, indicating insufficient evidence to conclude a lower prevalence in inner city residents. 2. Same as above but consider equivalence of the two proportions. 3. The data suggest the population proportion is significantly smaller than 14% at α = 0.05, suggesting sufficient evidence to conclude a lower prevalence in inner city residents.**Note:** This exercise guides learners through hypothesis testing for population proportions, highlighting key statistical concepts and decision-making strategies in educational settings.

Name: image attatched ### h. Interpret the p-value in the context of the stu
Uploaded: 2024-03-20T07:07:37.000Z
Channel: Bartleby
Description: image attatched ### h. Interpret the p-value in the context of the study.- ○ There is a 14% chance of a Type I error.- ○ If the population proportion of inner city residents who have sleep apnea is 14% and if another 369 inner city residents are surv

Thank you for posting this question! Since this question has multiple sub-parts, I will solve the first three sub-parts for you. To get the remaining sub-parts solved, please resubmit this complete question and mention the sub-parts to be solved. Solution: It is given that 14% of all Americans suffer from sleep apnea. A researcher suspects that a lower percentage of those who live in the inner city have sleep apnea. Thus, the population proportion of Americans who suffer from sleep apnea: p =0.14 Sample size: n = 369 Out of 369 people, the number of people who suffered from sleep apnea: x = 41 Part a) Foe this study, we should use one sample Z test for proportion. Part b) The null and alternative hypotheses would be: H0: p = 0.14 H1: p < 0.14 Part c) Test statistic is required to find. For that. we first need to find the sample proportion. The formula and calculation of test statistic is as follows: Rounding it to three decimal places, it becomes -1.599. The test statistic: z = -1.599