Use a 0.05 significance level to test the claim that there is a difference between the actual and reported heights, in inches, for 12-16 year old boys. The data is listed in the table below.Click the icon to view the data table of the reported heights.Let μ₁ denote the median of the first variable and μ₂ denote the median of the second variable. What are the null and alternative hypotheses?OA. Ho: H₁ H₂H₁: H₁ H₂C. Ho: H₁ H2H₁: H₁ H₂Find the test statistic.Test statistic = -2.26 (Round to two decimal places as needed.)CHMore InfoOB. Ho: H₁ H₂H₁: P1 P₂OD. Ho: ₁2H₂H₁ H₁ H₂Actual 61.9 67.9 71.2 61.4 62.3 68.8 65.9 70.8 61.9 66.7Reported 62 68 71 62 61 69 66 70 62 67Actual 59.6 71.9 64.5 64.4 71.9 69.1 68.8 68.1 71.7 62.5Reported 60 72 64 64 72 69 68 68 72 62Actual 65.2 59.9 64.8 65.5 67Reported 65 60 65 66 67Print68.7 65.2 71.4 69.2 60.969 65 72 69 61Done- X

T test is the type of parametric test. It follows the assumption of normal distribution. It compare…

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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instructor thinks that the mean score is higher. She samples 10 statistics students and obtains the scores: Grades 63.9 68.4 | 69 | 96 64.3 | 63.9 65 69 62.7 68.4 Test grades are believed to be normally distributed. Use a significance level of 5%. A. State the alternative hypothesis: HA: Ou + 65 Ομ 65 B. State the mean of the sample: C. State the standard error of the sample means:
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An instructor wanted to know if his students are better at math or writing. He had students take both a math and then a writing test and he compared the results using SPSS. He found the following results: ( look at graphs ) a. What test was done?b. Report results in APA style.
The average house has 15 paintings on its walls. Is the mean larger for houses owned by teachers? The data show the results of a survey of 16 teachers who were asked how many paintings they have in their houses. Assume that the distribution of the population is normal. 18, 15, 17, 14, 16, 17, 18, 15, 15, 14, 14, 14, 15, 15, 16, 18 What can be concluded at the a = 0.05 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Но: Select an answer v H1: Select an answer v c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? va f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the population mean is not significantly more than 15 at a = 0.05, so there is sufficient evidence to conclude that the population mean number of paintings that are in…
A random sample of 10,000 bottles of cola was taken to see whether the mean weight was 16 fluid ounces, as marked on the container. The null hypothesis is that the population mean is 16 ounces. Use the read-out below to test the hypothesis that the colas do not have a population mean of 16 fluid ounces. You do not have to do any calculations; just interpret the given data clearly and thoroughly in the context of the problem. | One-Sample T: ounces Test of u = 16 vs = 16 Variable Mean StDev SE Mean 95 CI T P ounces 10000 15.9988 0.0985 0.0010 (15.9969, 16.0007) -1.21 0.225
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You want to compare differences in prior arrests across ethnicity in your study, you measured ethnicity as white =0 black =1 hispanic=2, and other =3. Prior arrests was recorded as the number of prior arrests. which test would you perform to see if arrests differ across diffrent ethnic categories? A. ANOVA B. T-test
Fertilizer: A new type of fertilizer is being tested on a plot of land in an orange grove, to see whether it increases the amount of fruit produced. The mean number of pounds of fruit on this plot of land with the old fertilizer was 381 pounds. Agriculture scientists believe that the new fertilizer may increase the yield. State the appropriate null and alternate hypotheses. Answer the following question.
For the given scenario, determine the type of error that was made if any.(begin by determining the null and alternative hypothesis). A new whitening toothpaste advertises for shades as the mean number of shades the toothpaste whitens your teeth. One user claims that the mean number of shades the toothpaste whitens your teeth is different from four shades. The user conducts a hypothesis test and fails to reject the null hypothesis. Assume that in reality, the mean number of shades the two piece white is your teeth is for shade. Was an error made? If so, what type? A, B, C? A.Yes; type 2 error B.Yes; type 1 error C.No; correct decision
Question 2 > The average number of cavities that thirty-year-old Americans have had in their lifetimes is 7. Do twenty- year-olds have a different number of cavities? The data show the results of a survey of 14 twenty-year-olds who were asked how many cavities they have had. Assume that the distribution of the population is normal. 7, 8, 7, 7, 9, 7, 10, 9, 8, 10, 6, 9, 6, 8 What can be concluded at the a = 0.05 level of significance? %3D a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Но: |? Select an answer H1: Select an answer v c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? va f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that . The data suggest the populaton mean is significantly different from 7 at a = 0.05, so there is sufficient evidence to conclude that the…
A statistician changes her level of significance from .001 to .05. What impact will this change have on her risk of making a Type I and Type II error? Is the change in the level of significance a good decision? Why or why not?

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