how do i solve for parts A-G? ### Hypothesis Testing: Distracted Driving AnalysisThe Department of Transportation reports that out of all fatal crashes, 6% of the drivers were distracted at the time of the crash. You take a sample of 345 fatal crashes in Washington State and find that 25 of the drivers were distracted.#### Hypothesis Test:You want to test whether the proportion of crashes involving distracted drivers in Washington State is the same as the national average, to a significance level of 0.05.**a. What should the null and alternative hypotheses look like?**- \( H_0: p = 0.06 \)- \( H_A: p \ne 0.06 \)**b. Calculate the value of the point estimate.**\[ \hat{p} = \frac{25}{345} = 0.072 \]**c. Does this pass the success-failure condition?**- \(\checkmark\) Yes, this test passes the success-failure condition.- \( \quad \) No, this test does not pass the success-failure condition.**d. Compute the standard error.**\[ SE = \sqrt{\frac{p (1 - p)}{n}} \]\[ SE = \sqrt{\frac{0.06 (1 - 0.06)}{345}} \approx 0.013 \]**e. Compute the test statistic.**\[ z = \frac{\hat{p} - p_0}{SE} \]\[ z = \frac{0.072 - 0.06}{0.013} \approx 0.923 \]**f. What is the p-value?**\[ p\text{-value} \approx 0.36 \]**g. What conclusion should we draw regarding \( H_0 \)?**- \(\checkmark\) Fail to reject \( H_0 \)- \( \quad \) Reject \( H_0 \)Based on the results, we do not have enough evidence to suggest that the proportion of fatal crashes involving distracted drivers in Washington State is different from the national average.

Given,n=345x=25p^=xnp^=25345=0.0725α=0.05

The Department of Transportation reports that out of all fatal crashes, 6% of the drivers were distracted at the time of the crash. You take a sample of 345 fatal crashes in Washington State and find that 25 of the drivers were distracted. Hypothesis Test: You want to test whether the proportion of crashes involving distracted drivers in Washington State is the same as the national average, to a significance level of 0.05. a. What should the null and alternative hypotheses look like? Ho: p = 0.06 HA: P = 0.06 ( Ho: μ = 25 Η Α: μ + 25 Ho: P1 = 0 HA: B1 0 b. Calculate the value of the point estimate. c. Does this pass the success-failure condition? Yes, this test passes the success-failure condition. No, this test does not pass the success-failure condition. d. Compute the standard error. e. Compute the test statistic. f. What is the p-value? g. What conclusion should we draw regarding H? O Fail to reject H O Reject H

The Department of Transportation reports that out of all fatal crashes, 6% of the drivers were distracted at the time of the crash. You take a sample of 345 fatal crashes in Washington State and find that 25 of the drivers were distracted. Hypothesis Test: You want to test whether the proportion of crashes involving distracted drivers in Washington State is the same as the national average, to a significance level of 0.05. a. What should the null and alternative hypotheses look like? Ho: p = 0.06 HA: P = 0.06 ( Ho: μ = 25 Η Α: μ + 25 Ho: P1 = 0 HA: B1 0 b. Calculate the value of the point estimate. c. Does this pass the success-failure condition? Yes, this test passes the success-failure condition. No, this test does not pass the success-failure condition. d. Compute the standard error. e. Compute the test statistic. f. What is the p-value? g. What conclusion should we draw regarding H? O Fail to reject H O Reject H

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

how do i solve for parts A-G?

### Hypothesis Testing: Distracted Driving Analysis

The Department of Transportation reports that out of all fatal crashes, 6% of the drivers were distracted at the time of the crash. You take a sample of 345 fatal crashes in Washington State and find that 25 of the drivers were distracted.

#### Hypothesis Test:
You want to test whether the proportion of crashes involving distracted drivers in Washington State is the same as the national average, to a significance level of 0.05.

**a. What should the null and alternative hypotheses look like?**
- \( H_0: p = 0.06 \)
- \( H_A: p \ne 0.06 \)

**b. Calculate the value of the point estimate.**
\[ \hat{p} = \frac{25}{345} = 0.072 \]

**c. Does this pass the success-failure condition?**
- \(\checkmark\) Yes, this test passes the success-failure condition.
- \( \quad \) No, this test does not pass the success-failure condition.

**d. Compute the standard error.**
\[ SE = \sqrt{\frac{p (1 - p)}{n}} \]
\[ SE = \sqrt{\frac{0.06 (1 - 0.06)}{345}} \approx 0.013 \]

**e. Compute the test statistic.**
\[ z = \frac{\hat{p} - p_0}{SE} \]
\[ z = \frac{0.072 - 0.06}{0.013} \approx 0.923 \]

**f. What is the p-value?**
\[ p\text{-value} \approx 0.36 \]

**g. What conclusion should we draw regarding \( H_0 \)?**
- \(\checkmark\) Fail to reject \( H_0 \)
- \( \quad \) Reject \( H_0 \)

Based on the results, we do not have enough evidence to suggest that the proportion of fatal crashes involving distracted drivers in Washington State is different from the national average.

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