Required informationNOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part.The toggle shown in figure (a) is added to the tongs of figure (b) and the load is lifted by applying a single force at G.Given: W = 8040 lb.WAG35 in.55 in.A-73 in.14 in.45 in.BW55 in.B20 in.BDetermine the forces exerted at C and E on the tong BCE.The forces exerted at C on the tong BCE iskips.The forces exerted at E on the tong BCE iskips. 7

Then C = 16683 lb= 16.7 kipsand E= 10174.35 lb = 10.2 kips

Answered: Required information NOTE: This is a…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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X Your answer is incorrect. A flanged wooden shape is used to support the loads shown on the beam. The dimensions of the shape are shown in the second figure. Assume LAB - 8 ft, Lec-2 ft, Lco-3 ft. LDE-3 ft, Pc- 1870 lb. PE-2190 lb, WAE-650 lb/ft, b₁-9 in., b2-2 in., b3-6 in., d₁-2 in..d₂-7 in., d3-2 in. Consider the entire 16-ft length of the beam and determine: (a) the maximum tension bending stress o at any location along the beam, and (b) the maximum compression bending stress oc at any location along the beam. Answers: WAB LAB (a) GT = (b) σ, = i i 402.3 558.1 B Pr LBC by C IH by LCD b₂ psi. psi. D d₁ LDE dz dy РЕ E
Answer in this format. Sketch: Given: Required: Solution: (Please answer in detailed (step by step). Indicate labels on what you are doing/performing, for example what formula is used) An electrical worker stands in the bucket that hangs from a pin at end D of the boom of the cherry picker in Fig. 1. The worker and bucket together weigh a total of 300 lb. Between A and C the boom weighs 1.1 Įb/in., and between C and D it weighs 0.8 Jb/in. Assume that AC and CD are uniform beams. Determine the normal force, the transverse shear force, and the bending moment that act at cross section E, midway between A and B. В Eaxial Eshear Emoment Ib Ib Ib Ib in 50" 40" D 10"10 INDICATE WHETHER POSITIVE OR NEGATIVE |20° Bucket 60° Fig. 1 (a) “Bucket truck."
Please provide a complete step-by-step solution and free body diagram. Round off the final answer to four decimal places. Thank you!
Please provide factual solution and I will leave thumbs up
QUESTION 8 Find the force generated by the deltoid (right arm) if: His arm length (d) is: 0.84 m The COG of the arm is 37% away from the proximal end His arm weighs 7.9N The weight weighs 126 N The angle of the arm from vertical (@): = 90 degrees The deltoid insertion is 0.17 m from proximal end The line of pull for the deltoid is: 11 degrees Round to the nearest whole # and assume the final answer is positive. Leave no space between answer and units.
Required Information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. A Howe roof truss is shown. Take P₁= P₂= P3 = 600 lb. P2 300 b P1 BY CI P3 E SASHSA→→SA- The force in member AB (FAB) is The force in member AC (FAC) is The force in member BC (FBC) is The force in member CE (FCE) is The force in member BD (FBD) is The force in member BE (FB) is The force in member DF (FDA) is The force in member DE (FDE) is The force in member EF (FEA) is The force in member EG (FEG) is The force in member FG (FFG) is The force in member FH (FFH) is The force in member GH (FGH) is 300 lb 6 ft G H 6 ft Determine the force in each member of the Howe roof truss shown. State whether each member is in tension (7) or compression (C). lb (Click to select) V lb (Click to select) lb (Click to select) lb (Click to select) lb (Click to select) lb (Click to select) lb (Click to select) lb (Click to select) lb (Click to select) V lb (Click to select) lb…
MECHANICS OF DEFORMABLE BODIES (UPVOTE WILL BE GIVEN. PLEASE WRITE THE COMPLETE SOLUTION LEGIBLY AND DRAW THE FBDs. ANSWER IN 2 DECIMAL PLACES. NO LONG EXPLANATION NEEDED. BOX THE FINAL ANSWER.) *Diameter of the cables supporting the crate is 1/4. Express the answers in psi. Solve item (iv) only
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Isometric View: K 30.5in (from left edge of load to right edge of load) 1.5in 6.5in 1.5in 6.5in 1.5in 6.5in 1.5in 156 6.5in 1.5in Top View: 15lbs 15lbs 15lbs 15lbs 33.5in (length of rod) 30.5in (from left edge of load to right edge of load) 1.5in 6.5in 1.5in 6.5in * Ж- 1.5in 6.5in 1.5in 6.5in 1.5in 15 lbs Cross-section View: 15 lbs 15 lbs 12in diameter 33.5in (length of rod) 15 lbs 15 lbs 4 cylindrical masses that weigh 15 lbs each are being supported by 2 solid stainless steel rods. The two rods are secured at both ends, the rest of the rod is suspended. Determine the minimum rod diameter that the 2 rods must have to support the loads without bending.
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a)Consider the cable supporting the hook, and thus the load. The magnitude of the internal force within the "left-piece" of the cable at 1.25m above the sheave is _____ kN. b) Consider the cable supporting the hook, and thus the load. The state of the internal force within the "left-piece" of the cable at 1.25m above the sheave is _____ . NOTE: Enter "1" for "tension". Enter "2" for "compression" Enter "3" for "torsion" Enter "4" for "neither tension, nor compression, nor torsion c)Consider the cable between the input power sheave and the Sheave-G. The magnitude of the internal force within this cable at 1.667m from the center of Sheave-G is _____ kN. d) Consider the cable between the input power sheave and the Sheave-G. The state of the internal force within this cable at 1.667m from the center of Sheave-G is _____ . NOTE: Enter "1" for "tension". Enter "2" for "compression" Enter "3" for "torsion" Enter "4" for "neither tension, nor compression, nor torsion e) The state of the…

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