rees A student performs a test of Ho p = 0.75 versus H, p<0.75 at the a = 0.05 significance level and gets a P-value of 0.22. The student writes: "Because the P-value is large, we accept Ho. The data provide convincing evidence that the null hypothesis is true." What should the student have written for their conclusion? Because the P-value is large, we fail to reject Ho. The data do not provide convincing evidence that the alternative hypothesis is true. Because the P-value is large, we fail to reject Ho. The data provide convincing evidence that the alternative hypothesis is true. Because the P-value is small, we reject Ho. The data provide convincing evidence that the alternative hypothesis is true. Because the P-value is large, we accept Ho. The data do not provide convincing evidence that the alternative hypothesis is true. What the student wrote is correct. Incorect

rees A student performs a test of Ho p = 0.75 versus H, p<0.75 at the a = 0.05 significance level and gets a P-value of 0.22. The student writes: "Because the P-value is large, we accept Ho. The data provide convincing evidence that the null hypothesis is true." What should the student have written for their conclusion? Because the P-value is large, we fail to reject Ho. The data do not provide convincing evidence that the alternative hypothesis is true. Because the P-value is large, we fail to reject Ho. The data provide convincing evidence that the alternative hypothesis is true. Because the P-value is small, we reject Ho. The data provide convincing evidence that the alternative hypothesis is true. Because the P-value is large, we accept Ho. The data do not provide convincing evidence that the alternative hypothesis is true. What the student wrote is correct. Incorect

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

In a study of high school students at least 16 years of age, researchers obtained survey results summarized in the accompanying table. Use a 0.05 significance level to test the claim of independence between texting while driving and driving when drinking alcohol. Are those two risky behaviors independent of each other? Click the icon to view the table of survey results. Determine the null and alternative hypotheses. H₂: H₁: Determine the test statistic. x² = (Round to two decimal places as needed.) Determine the P-value of the test statistic. ▼ P-value = (Round to three decimal places as needed.) Do the results suggest that texting while driving and driving while drinking are related? C Survey Results Texted While Driving No Texting While Driving Print Drove When Drinking Alcohol? Yes No 735 151 Done 3036 4489 X O A. Fail to reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that texting while driving happens 95% of the time when driving…
Test the claim that the proportion of men who own cats is significantly different than 15% at the 0.01 significance level. The null and alternative hypothesis would be: Ho:p 0.15 Ho:p= 0.15 Ho:u = Ho:u= Ho:= Ho:p 0.15 o H1:p> 0.15 H:p H:p# H: < H:p 0.15 |3D %3D O.
State your decision to the significance test in terms of the null hypothesis.According to a recent poll, the percentage of Americans who would vote for the incumbent president is 53%. If a random sample of 100 people in New York results in 45% who would vote for the incumbent, test the claim that the percentage of people in New York who would vote for the incumbent president is different from 53%. Use the following results and a 0.10 significance level to state your decision about H0. H0 : p=0.53 HA : p≠0.53 Test statistic: z = -1.60 p-value = 0.1090 Question options a) Do not reject HA b) There is not enough information. c) Reject HA d) Do not reject H0 e) Reject H0
You wish to test the following claim (Ha) at a significance level of α=0.05. Ho:p1≤p2Ho:p1≤p2 Ha:p1>p2Ha:p1>p2You obtain a sample from the first population with 75 successes and 587 failures. You obtain a sample from the second population with 15 successes and 253 failures. test statistic = [three decimal accuracy] p-value = [four decimal accuracy] The p-value is... less than (or equal to) αα greater than αα This test statistic leads to a decision to... reject the null hypothesis fail to reject the null hypothesis As such, the final conclusion is that... There is sufficient evidence to support that the first population proportion is greater than the second population proportion. There is not sufficient evidence to support that the first population proportion is greater than the second population proportion.
Jacqueline, a medical researcher, would like to make the claim that a newly developed prescription medication for headaches gives patients relief in 61 minutes or less, on average. Jacqueline samples 12 users of the medication and obtains a sample mean of 55 minutes. At the 1% significance level, should Jacqueline reject or fail to reject the null hypothesis given the sample data below? H0:μ=61 minutes; Ha:μ<61 minutes α=0.01 (significance level) test statistic=−1.99 Use the graph below to select the type of test (left-, right-, or two-tailed). Then set the α and the test statistic to determine the p-value. Use the results to determine whether to reject or fail to reject the null hypothesis. Select the correct answer below: 1) Reject the null hypothesis because |−1.99|>0.01. 2) Do not reject the null hypothesis because |−1.99|>0.01. 3) Reject the null hypothesis because the p-value 0.0233 is greater than the significance level α=0.01. 4)…
This is the full question
A hypothesis test was used to test the hypothesis that people with a significant other are happier on average than people without. The P-value was 0.07 and the level of significance used was 0.1. Then there is sufficient evidence to conclude that, on average, people with a significant other are happier than single people. True or False
Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .05 significance level. The null and alternative hypothesis would be: Ho: HM = HF H,:PM = PF Ho: HM = PF Ho:HM = Pr Ho:PM = Pr Ho:PM PF H1: HM PF H1:HM > HF H1:HM # HF H1:PM + PF H1:PM < Pf The test is: right-tailed two-tailed left-tailed Based on a sample of 40 men, 40% owned cats Based on a sample of 40 women, 65% owned cats The test statistic is: (to 2 decimals) The p-value is: (to 4 decimals) Based on this we: O Reject the null hypothesis OFail to reject the null hypothesis Check Answer
Test the claim that the proportion of people who own cats is significantly different than 30% at the 0.01 significance level. The null and alternative hypothesis would be: 0.3 Но: р > 0.3 Но:р > 0.3 Но:р — 0.3 Но:р 0.3 H1 :µ + 0.3 H1: H 0.3 The test is: two-tailed right-tailed left-tailed Based on a sample of 800 people, 39% owned cats The p-value is: (to 2 decimals) Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
The test statistic of z=2.40 is obtained when testing the claim that p>0.7. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. Find the P-value. Using a significance level of α=0.10, should we reject H0 or should we fail to reject H0?
Test the claim that the mean GPA of night students is significantly different than 3.2 at the 0.2 significance level.The null and alternative hypothesis would be: (multiple choice) H0:p=0.8H0:p=0.8H1:p>0.8H1:p>0.8 H0:μ=3.2H0:μ=3.2H1:μ>3.2H1:μ>3.2 H0:p=0.8H0:p=0.8H1:p<0.8H1:p<0.8 H0:μ=3.2H0:μ=3.2H1:μ≠3.2H1:μ≠3.2 H0:μ=3.2H0:μ=3.2 H1:μ<3.2H1:μ<3.2 H0:p=0.8H0:p=0.8H1:p≠0.8H1:p≠0.8 The test is: (multiple choice) left-tailed right-tailed two-tailed Based on a sample of 30 people, the sample mean GPA was 3.17 with a standard deviation of 0.07The test statistic is: (to 2 decimals)The positive critical value is: (to 2 decimals)Based on this we: (multiple choice) Reject the null hypothesis Fail to reject the null hypothesis
Assume a significance level of a = 0.05 and use the given information to complete parts (a) and (b) below. Original claim: More than 46% of adults would erase all of their personal information online if they could. The hypothesis test results in a P-value of 0.2575. a. State a conclusion about the null hypothesis. (Reject Ho or fail to reject Ho.) Choose the correct answer below. CHE OA Reject Ho because the P-value is greater than a. OB. Reject Ho because the P-value is less than or equal to a. OC. Fail to reject Ho because the P-value is greater than a. OD. Fail to reject Ho because the P-value is less than or equal to a. b. Without using technical terms, state a final conclusion that addresses the original claim. Which of the following is the correct conclusion? OA. There is sufficient evidence to support the claim that the percentage of adults that wo erase all of their personal information online if they could is more than 46%. OB. The percentage of adults that would erase all of…