The test statistic of z=2.40 is obtained when testing the claim that p>0.7. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. Find the P-value. Using a significance level of α=0.10, should we reject H0 or should we fail to reject H0?
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The test statistic of z=2.40
is obtained when testing the claim that p>0.7.
- Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed.
- Find the P-value.
- Using a significance level of α=0.10, should we reject H0 or should we fail to reject H0?
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- The test statistic in a two-tailed test is z=−2.61.Determine the P-value and decide whether, at the 5% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. The P-value is? (Round to four decimal places as needed.)You are conducting a hypothesis test where the null hypothesis is that true population mean is less than or equal to 180. Your test will be at the 0.10 significance level. You take a sample of size n=60, and find that the sample average is 185, and the STANDARD ERROR is 15. What is the value of your test statistic? (Please answer to two decimal places. ex: 5.43)The mean GPA of night students is significantly different than the mean GPA of day students at the 0.01 significance level. Null and alternative hypothesis? H0:μN=μD H1:μN≠μD When it says "significantly different" would we choose the option with the line going through the equal sign? The test is: two-tailed (Is this the choice for a hypothesis that has an equal sign with the line through it? left-tailed right-tailed Sample of 75-night students, a sample mean GPA of 3.47 and an SD of 0.03 Sample of 35-day students, a sample mean GPA of 3.45 and an SD of 0.04. The test statistic is: Do we use the z test or interval function on the calculator? The positive critical value is: How do we solve for critical value and then use this info to figure out if the hypothesis was rejected or failed? < Based on this we: Reject the null hypothesis OR Fail to reject the null hypothesis
- Test the claim that the mean GPA of night students is significantly different than the mean GPA of day students at the 0.1 significance level.The null and alternative hypothesis would be: H0:μN=μDH0:μN=μDH1:μN≠μDH1:μN≠μD H0:μN=μDH0:μN=μDH1:μN>μDH1:μN>μD H0:pN=pDH0:pN=pDH1:pN≠pDH1:pN≠pD H0:pN=pDH0:pN=pDH1:pN>pDH1:pN>pD H0:pN=pDH0:pN=pDH1:pN<pDH1:pN<pD H0:μN=μDH0:μN=μDH1:μN<μDH1:μN<μD The test is: two-tailed left-tailed right-tailed The sample consisted of 45 night students, with a sample mean GPA of 2.15 and a standard deviation of 0.06, and 35 day students, with a sample mean GPA of 2.16 and a standard deviation of 0.03.The test statistic is: ________(to 2 decimals)The positive critical value is: ________(to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesisTest the claim that the mean GPA of night students is smaller than 3.4 at the 0.025 significance level. The null and alternative hypothesis would be: Ho:p = 0.85 Ho:µ 0.85 Ho:µ= 3.4 Ho:µ > 3.4 H1:p + 0.85 H1:µ > 3.4 H1:p > 0.85 H1:p < 0.85 H1:µ # 3.4 H1:µ < 3.4 The test is: right-tailed two-tailed left-tailed Based on a sample of 20 people, the sample mean GPA was 3.39 with a standard deviation of 0.02 The p-value is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesisTest the claim that the mean GPA of night students is smaller than 2.4 at the .05 significance level.The null and alternative hypothesis would be: H0:μ=2.4H0:μ=2.4H1:μ>2.4H1:μ>2.4 H0:p=0.6H0:p=0.6H1:p≠0.6H1:p≠0.6 H0:μ=2.4H0:μ=2.4H1:μ<2.4H1:μ<2.4 H0:p=0.6H0:p=0.6H1:p<0.6H1:p<0.6 H0:p=0.6H0:p=0.6H1:p>0.6H1:p>0.6 H0:μ=2.4H0:μ=2.4H1:μ≠2.4H1:μ≠2.4 The test is: right-tailed two-tailed left-tailed Based on a sample of 60 people, the sample mean GPA was 2.37 with a standard deviation of 0.02The test statistic is: (to 2 decimals)The critical value is: (to 2 decimals)
- Test the claim that the mean GPA of night students is larger than 3.1 at the 0.10 significance level.The null and alternative hypothesis would be: H0:p=0.775H0:p=0.775H1:p≠0.775H1:p≠0.775 H0:p=0.775H0:p=0.775H1:p>0.775H1:p>0.775 H0:μ=3.1H0:μ=3.1H1:μ>3.1H1:μ>3.1 H0:μ=3.1H0:μ=3.1H1:μ<3.1H1:μ<3.1 H0:p=0.775H0:p=0.775H1:p<0.775H1:p<0.775 H0:μ=3.1H0:μ=3.1H1:μ≠3.1H1:μ≠3.1 The test is: right-tailed two-tailed left-tailed Based on a sample of 75 people, the sample mean GPA was 3.14 with a standard deviation of 0.03The test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we fail to reject the null hypothesis. reject the null hypothesis.A claim is made that the proportion of children who play sports is less than it used to be. Assume that you plan to use a significance level of αα = 0.05 to test the claim that p<0.5p<0.5. Find the critical value for this hypothesis test, then use x=396x=396 and n=1320n=1320 from the sample data to decide if the statistics support the claim. -1.96; yes, they do support the claim -1.96; no, they do not support the claim -1.645; yes, they do support the claim -1.645; no, they do not support the claimFind the P-value for the indicated hypothesis test with the given standardized test statistic, z. Decide whether to reject H0 for the given level of significance α. Two-tailed test with test statistic z=−1.86 and α=
- Test the claim that the mean GPA of night students is larger than the mean GPA of day students at the .01 significance level.The null and alternative hypothesis would be: H0:pN=pDH0:pN=pDH1:pN>pDH1:pN>pD H0:pN=pDH0:pN=pDH1:pN<pDH1:pN<pD H0:μN=μDH0:μN=μDH1:μN>μDH1:μN>μD H0:μN=μDH0:μN=μDH1:μN<μDH1:μN<μD H0:μN=μDH0:μN=μDH1:μN≠μDH1:μN≠μD H0:pN=pDH0:pN=pDH1:pN≠pDH1:pN≠pD The test is: two-tailed right-tailed left-tailed The sample consisted of 25 night students, with a sample mean GPA of 3.43 and a standard deviation of 0.03, and 30 day students, with a sample mean GPA of 3.38 and a standard deviation of 0.02.The test statistic is: ______ (to 2 decimals)The critical value is: ________(to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesisA medical equipment manufacturer believes that the proportion of faulty blood pressure monitors is greater than 0.11, the proportion stated by the supplier. We perform a hypothesis test at a significance level of 0.05 with the null and alternative hypothesis as follows: Ho: p = 0.11 and Ha: p < 0.11. A researcher inspects 150 items and finds 25 faulty ones. She gives a p-value of 0.01 in her analysis. Which of the following definitions is the correct interpretation of the p-value? O The probability of getting 25 or more faulty blood pressure monitors out of 150 if the true faulty rate is 0.11. The value that the z-statistic must be less than in order to reject the null hypothesis. The probability of rejecting a true null hypothesis. O The probability that the true rate of faulty items is 0.01.A running shoe manufacturer believes that its supply of faulty running shoes is less than 0.03, the rate deemed acceptable. We perform a hypothesis test at a significance level of 0.05 with the null and alternative hypothesis as follows: Ho: p = 0.03 and Ha:p < 0.03. Choose the statement that best describes the significance level in the context of the hypothesis test. The significance level of 0.05 is X the probability of concluding that the faulty rate is less than 0.03 when in fact the faulty rate is equal to 0.03. the z-statistic that we will use to compare the observed outcome to the null hypothesis. the rate of faulty monitors that we believe is the true rate. O the probability of concluding that the faulty rate is equal to 0.03 when in fact it is less than 0.03.