In a study of high school students at least 16 years of age, researchers obtained survey results summarized in the accompanying table. Use a 0.05 significance level to test the claim of independence between texting while driving and driving when drinking alcohol. Are those tworisky behaviors independent of each other?Click the icon to view the table of survey results.Determine the null and alternative hypotheses.H₂:H₁:Determine the test statistic.x² = (Round to two decimal places as needed.)Determine the P-value of the test statistic.▼P-value =(Round to three decimal places as needed.)Do the results suggest that texting while driving and driving while drinking are related?CSurvey ResultsTexted While DrivingNo Texting While DrivingPrintDrove When Drinking Alcohol?YesNo735151Done30364489XO A. Fail to reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that texting while driving happens 95% of the time when driving while drinking alcohol.O B. Reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that texting while driving happens 95% of the time when driving while drinking alcohol.O C. Fail to reject the null hypothesis. There is not sufficient evidence at a 0.05 significance level to warrant rejection of the claim of independence between texting while driving and driving while drinking alcohol. Those two risky behaviors are not related.O D. Reject the null hypothesis. There is sufficient evidence at a 0.05 significance level to warrant rejection of the claim of independence between texting while driving and driving while drinking alcohol. Those two risky behaviors appear to be somehow related. In a study of high school students at least 16 years of age, researchers obtained survey results summarized in the accompanying table. Use a 0.05 significance level to test the claim of independence between texting while driving and driving when drinking alcohol. Are those tworisky behaviors independent of each other?Click the icon to view the table of survey results.Determine the null and alternative hypotheses.Ho:H₁:Detex²==DeteP-vaSurvey ResultsDo tlTexted While DrivingNo Texting While DrivingDrove When Drinking Alcohol?YesNo735151PrintTexting while driving is independent of driving while drinking alcohol.Texting while driving and other risky behaviors are dependent.Texting while driving and driving while drinking alcohol are dependent.Texting while driving is independent of all other risky behaviors.OAO B.ection of the claim that texting while driving happens 95% of the time when driving while drinking alcohol.Reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that texting while driving happens 95% of the time when driving while drinking alcohol.O C. Fail to reject the null hypothesis. There is not sufficient evidence at a 0.05 significance level to warrant rejection of the claim of independence between texting while driving and driving while drinking alcohol. Those two risky behaviors are not related.O D. Reject the null hypothesis. There is sufficient evidence at a 0.05 significance level to warrant rejection of the claim of independence between texting while driving and driving while drinking alcohol. Those two risky behaviors appear to be somehow related.30364489DoneDX

The given table is Drove when Drinking Alcohol? Yes No Texted While Driving 735 3036 No…

Answered: Determine the null and alternative…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The null and alternate hypotheses are: He: T1 T₂ H₁: T₁ T₂ A sample of 100 observations from the first population indicated that x₁ is 70. A sample of 150 observations from the second population revealed x₂ to be 90. Use the 0.05 significance level to test the hypothesis. a. State the decision rule. (Round your answer to 2 decimal places.) HO is rejected if z> b. Compute the pooled proportion. (Round your answer to 2 decimal places.) Pooled proportion
Testing men and womens views on what age is ideal to get married. Sample: men=25 women=26. Asked them what their ideal age would be to get married. Men: mean=24.11 std. Dev.=2.19 n=25 Women: mean=21.79. Std. Dev.:=2.20 n=26 A. State the null and research hypotheses, b. Idebtify critical values of z or t used to define the decision rule, c. Calculate the test statistic, d. Report p-value, e. Report your findings
A null hypothesis states that p=.3, the observed sample proportion is p= 41 with a sample size of n-67. Determine the z-score. O 0.82 O-1.47 O-0.91 O 1.96
urses e Home mments ent Gradebook Crunch xt Contents Suppose that in a random selection of 100 colored candies, 24% of them are blue. The candy company claims that the percentage of blue candies is equal to 28%. Use a 0.10 significance level to test that claim. deo and Resource Identify the null and alternative hypotheses for this test. Choose the correct answer below. OA. Ho: p=0.28 H₁: p>0.28 OB. Ho: p=0.28 H₁: p 0.28 OC. Ho: p=0.28 H₁: p<0.28 OD. Ho: p0.28 H₁: p= 0.28 Identify the test statistic for this hypothesis test. Type here to search Help me solve this View an example O G Get more help - C 99+ 4 1 - 26 of 26 72°F Next
p5wrong 0.0323 1.848
In 1992 a national vital statistics report indicated that about 2.3% of all births produced twins. Is the rate of twin births the same among very young mothers? Data from a large city hospital found only 7 sets of twins were born to 455 teenage girls. Test an appropriate hypothesis and state your conclusion. Be sure the appropriate assumptions and conditions are satisfied before you proceed. Are the assumptions and the conditions to perform a one-proportion z-test met? ... No Yes State the null and alternative hypotheses. Choose the correct answer below. A. Ho: p=0.023 HA: P >0.023 B. Ho: p=0.023 HA: P = 0.023 C. Ho: p=0.023 HA: P<0.023 D. The assumptions and conditions are not met, so the test cannot proceed. Determine the z-test statistic. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. OA. Z= (Round to two decimal places as needed.) OB. The assumptions and conditions are not met, so the test cannot proceed.
State your conclusion to the hypothesis test. 21. A sociologist was interested in determining if there was a relationship between the age of a young adult (18 to 35 years old) and the type of movie preferred. A random sample of 93 adults revealed the following data. Use a Chi-Square independence test to determine if age and type of movie preferred are independent at the 5% level of significance. 18-23 years old 24-29 years old 30-35 years old Totals Drama 8 15 11 34 Science Fiction 12 10 8 30 Comedy 8. 12 29 Totals 29 33 31 93 Provided the assumptions of the test are satisfied, state your conclusion to the test. Note: the p-value = 0.4594 a) Cannot be determined. b The data suggests that age and type of movie preferred are not independent. The data does not suggest that age and type of movie preferred are independent. c) The data does not suggest that age and type of movie preferred are dependent. d) The data suggests that age and type of movie preferred are dependent. . e)
Use the data below to test the claim that the weight loss was greater with the low fat diet compared to the low carbohydrate diet. Use a 10% level of significance. Low Fat Low Carbohydrate x¯1=3.7lbs 1=5.2lb n1=57 x¯1=2.7 lbs1=4.9lb n1=62 Identify the tail of the test. What is the P-value? Will the null hypothesis be rejected? Is the initial claim supported?
A. Test the claim that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda. What are the null and alternative and hypotheses? B. What is the test statistic? (Round to two decimal places as needed.) C. What is the P-value? (Round to three decimal places as needed.) State the conclusion for the test. A. Reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda.B. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda.C. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda.D. Reject the null hypothesis. There is not sufficient evidence to support…
sanjay
A politician claims that the mean salary for managers in his state is more than the national mean, $84,000. Assume the the population is normally distributed and the population standard deviation is $7700. The salaries (in dollars) for a random sample of 30 managers in the state are listed. At a = 0.01, is there enough evidence to support the claim? Use technology. 80,874 89,459 95,542 87,349 83,781 88,302 85,753 93,786 91,229 90,606 91,146 80,279 93,679 77,478 82,344 85,484 96,253 77,709 74,771 71,775 77,218 85,416 78,102 89,432 95,180 73,518 88,662 72,601 71,633 74,338 (a) Identify the null hypothesis and alternative hypothesis. O A. Ho: H = 84,000 Ο Β. Ho: μ> 84,000 Ha:Hs 84,000 CC. Ho: us 84,000 Ha: u>84,000 Ha:H#84,000 O D. Ho: H 84,000 O E. Ho: H284,000 Ha:H84,000 Ha: µ = 84,000 Ha: H5 84,000 (b) Identify the standardized test statistic. (Round the final answer to two places as needed. Round all intermediate values to three places as needed.)
Express the null hypothesis and the alternative hypothesis in symbolic form. Use the correct symbol (μ or p) for the indicated parameter.The mean college professors' salary is claimed to be over $80,300.

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	Drove when Drinking Alcohol?
	Yes	No
Texted While Driving	735	3036
No Texting While Driving	151	4489