Reagent Table Reagent MD Molecular Mmol MEq Weight (g/ml) NaBH4 37.83 g/mol 1.412g 37.01 1.13 Vanillin Methanol 152.15g/mol 0.791g/ml 5.00g 32.86 1 5.00ml solvent solvent Example: Calculations Theoretical yield: 5.000 g 4-aminobenzoic acid x 1mol 137.14g -) = .03646 mol 4-aminobenzoic acid 1mol product .03646 mol 4 aminobenzoic acid x .03646 mol ethyl-4-aminobenzoate 1mol starting material .03646 mol ethyl-4-aminobenzoate x (165.199) = 6.023g ethyl-4-aminobenzoate % yield 5.112g x 100 = 84.9% yield 6.023g 1mol

Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter20: Environmental Chemistry-earth's Environment, Energy, And Sustainability
Section: Chapter Questions
Problem 41PS
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  1. Use the chart to calculate the theoretical yield, the example provided please create one like the example using the reagent table info show work please, I'm lost. This is not graded work this is a word for notes 
Reagent Table
Reagent
MD
Molecular
Mmol
MEq
Weight (g/ml)
NaBH4
37.83 g/mol
1.412g
37.01
1.13
Vanillin
Methanol
152.15g/mol
0.791g/ml
5.00g
32.86
1
5.00ml
solvent
solvent
Example:
Calculations
Theoretical yield:
5.000 g 4-aminobenzoic acid x
1mol
137.14g
-) = .03646 mol 4-aminobenzoic acid
1mol product
.03646 mol 4 aminobenzoic acid x
.03646 mol ethyl-4-aminobenzoate
1mol starting material
.03646 mol ethyl-4-aminobenzoate x (165.199) = 6.023g ethyl-4-aminobenzoate
% yield
5.112g x 100 = 84.9% yield
6.023g
1mol
Transcribed Image Text:Reagent Table Reagent MD Molecular Mmol MEq Weight (g/ml) NaBH4 37.83 g/mol 1.412g 37.01 1.13 Vanillin Methanol 152.15g/mol 0.791g/ml 5.00g 32.86 1 5.00ml solvent solvent Example: Calculations Theoretical yield: 5.000 g 4-aminobenzoic acid x 1mol 137.14g -) = .03646 mol 4-aminobenzoic acid 1mol product .03646 mol 4 aminobenzoic acid x .03646 mol ethyl-4-aminobenzoate 1mol starting material .03646 mol ethyl-4-aminobenzoate x (165.199) = 6.023g ethyl-4-aminobenzoate % yield 5.112g x 100 = 84.9% yield 6.023g 1mol
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