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Initial Change Equilibrium Solution Concentration Absorbance Fe3+ SCN- FeSCN²+ 0.00 Table 1: Standard Solutions for FeSCN2+ Beer's Law Plot Solution [Fe3+] [SCN] S1 (blank) 4.0 x 10-2 M 0.0 M S2 4.0 x 10-2 M 4.0 x 10-5 M S3 4.0 x 10-2 M 8.0 x 10-5 M S4 4.0 x 10-2 M 12.0 x 10-5 M S5 4.0 x 10-2 M 16.0 x 10-5 M S6 4.0 x 10-2 M 20.0 x 10-5 M Solution Volume in mL of 0.00200 M Fe(NO3)3 Table 2: Volumes for Unknown Equilibrium Solutions Volume in mL of 0.10 M HNO3 Volume in mL of 0.00200 M NaSCN E1 (blank) 5.00 0.00 5.00 E2 5.00 1.00 4.00 E3 5.00 2.00 3.00 E4 5.00 3.00 2.00 E5 5.00 4.00 1.00 E6 5.00 5.00 0.00

Initial Change Equilibrium Solution Concentration Absorbance Fe3+ SCN- FeSCN²+ 0.00 Table 1: Standard Solutions for FeSCN2+ Beer's Law Plot Solution [Fe3+] [SCN] S1 (blank) 4.0 x 10-2 M 0.0 M S2 4.0 x 10-2 M 4.0 x 10-5 M S3 4.0 x 10-2 M 8.0 x 10-5 M S4 4.0 x 10-2 M 12.0 x 10-5 M S5 4.0 x 10-2 M 16.0 x 10-5 M S6 4.0 x 10-2 M 20.0 x 10-5 M Solution Volume in mL of 0.00200 M Fe(NO3)3 Table 2: Volumes for Unknown Equilibrium Solutions Volume in mL of 0.10 M HNO3 Volume in mL of 0.00200 M NaSCN E1 (blank) 5.00 0.00 5.00 E2 5.00 1.00 4.00 E3 5.00 2.00 3.00 E4 5.00 3.00 2.00 E5 5.00 4.00 1.00 E6 5.00 5.00 0.00

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter18: Electrochemistry
Section: Chapter Questions
Problem 3RQ: Table 17-1 lists common half-reactions along with the standard reduction potential associated with...
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Absorbance values: 0, 0.127, 0.282, 0.432, 0.576, and 0.710. Plus the heat of 0.710 is 0.583 in a warm bath of 59.6 C. 
y = mx +b which is "y= 3605x- 0.006"
• Y = absorbance, m = slope, x = concentration, b = y-intercept
1. Determine the unknown concentration of your mixtures from your measured absorbances
• Solve the best fit line equation for x for each equilibrium mixture (E1-E6)
3. Set up ICE tables for each E mixture to find [Fe3+] and [SCN-] at
equilibrium for each
• Use the given amounts and concentrations from Table 2 for your initial [Fe3+] and [SCN-]
• Use your equilibrium concentrations from the previous step for your [FeSCN2+]eq
4. Calculate Kf
• Use your calculations of [Fe3+], [SCN-] and [FeSCN2+] to find Kf:
• kf = [FeSCN2+][Fe3+][SCN−]
Initial Change Equilibrium Solution Concentration Absorbance Fe3+ SCN- FeSCN²+ 0.00
Transcribed Image Text:Initial Change Equilibrium Solution Concentration Absorbance Fe3+ SCN- FeSCN²+ 0.00
Table 1: Standard Solutions for FeSCN2+ Beer's Law Plot Solution [Fe3+] [SCN] S1 (blank) 4.0 x 10-2 M 0.0 M S2 4.0 x 10-2 M 4.0 x 10-5 M S3 4.0 x 10-2 M 8.0 x 10-5 M S4 4.0 x 10-2 M 12.0 x 10-5 M S5 4.0 x 10-2 M 16.0 x 10-5 M S6 4.0 x 10-2 M 20.0 x 10-5 M Solution Volume in mL of 0.00200 M Fe(NO3)3 Table 2: Volumes for Unknown Equilibrium Solutions Volume in mL of 0.10 M HNO3 Volume in mL of 0.00200 M NaSCN E1 (blank) 5.00 0.00 5.00 E2 5.00 1.00 4.00 E3 5.00 2.00 3.00 E4 5.00 3.00 2.00 E5 5.00 4.00 1.00 E6 5.00 5.00 0.00
Transcribed Image Text:Table 1: Standard Solutions for FeSCN2+ Beer's Law Plot Solution [Fe3+] [SCN] S1 (blank) 4.0 x 10-2 M 0.0 M S2 4.0 x 10-2 M 4.0 x 10-5 M S3 4.0 x 10-2 M 8.0 x 10-5 M S4 4.0 x 10-2 M 12.0 x 10-5 M S5 4.0 x 10-2 M 16.0 x 10-5 M S6 4.0 x 10-2 M 20.0 x 10-5 M Solution Volume in mL of 0.00200 M Fe(NO3)3 Table 2: Volumes for Unknown Equilibrium Solutions Volume in mL of 0.10 M HNO3 Volume in mL of 0.00200 M NaSCN E1 (blank) 5.00 0.00 5.00 E2 5.00 1.00 4.00 E3 5.00 2.00 3.00 E4 5.00 3.00 2.00 E5 5.00 4.00 1.00 E6 5.00 5.00 0.00
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