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- 4. Use the reactant below to perform two separate reactions. Give the mechanism(s) and product(s) for each reaction. Show stereochemistry and be clear in your work. Use chair form. KOEt, EtOH t-Bu |||| H3O+Draw the two major products of this reaction. Use wedge and dash bonds to indicate stereochemistry where appropriate. Ignore inorganic byproducts. 1. BH3-THF 2.H2O2, NaOH, H₂O M iDraw the products for the following chemical reactions, indicating stereochemistry wherever applicable. Indicate if the reaction proceeds via SN1 or SN2 mechanism
- Draw the structures of the major organic product(s) or condition(s) denoted by A to E in the following reactions. Show stereochemistry of products, if any.Using curved-arrow notation, draw out the mechanism for the following reaction. Be sure to include stereochemistry and show all intermediates as well as the final product and include all lone pair electrons. Br Br2, H2O OHThe reaction of methylpropene with HBr in ether gives one of the two products below as the major product. Br HBr Br ether Product A Product B Product would have a higher energy transition state for the formation of the intermediate leading to it. O A O B O Both products would have the same transition state.
- 2. Consijder the reactiojn scheme below a. Draw the major product of this reaction. Show clearly (using wedge-and-dash lines) all stereoisomers formed under these reaction conditions. 1. BH3:THF 2. H2O2, NaOH b. What is the stereochemical relationship between the different stereoisomer products you drew in part 2a.?Draw the major products of this reaction. Ignore stereochemistry. Ignore inorganic byproducts. 1. KMnO4, H3O+ 2. NaIO4 3. Na2S2O3, H₂O Select to DrawWhat reagent/reagents is/are necessary to transform the starting molecule into the desired product? OH ? CH;CHCH,CH || CH3CH
- 4) For the following reaction map, provide the products, or reagents/ direction of the reaction arrow! MeO OMe MeO OHWhich statement is false regarding the following system? + HX Addition Elimination H -X O A positive AG means that the equilibrium will favor the reactants because the entropy term is larger than the enthalpy term representing the gain of entropy when one molecule becomes two. O A negative AG means that the equilibrium will favor the products because the enthalpy term is larger than the entropy term representing the loss of entropy when two molecules become one. Elimination reactions are thermodynamically favored at high temperatures, where the entropy of the reaction will be larger than the enthalpy, causing a positive AG and the reactants to be favored over the products. Addition reactions are thermodynamically favored at high temperatures, where the entropy of the reaction will be larger than the enthalpy, causing a positive AG and the reactants to be favored over the products.Each of these reaction produces ONE MAJOR PRODUCT. In each case, draw this product in the box provided, including appropriate stereochemistry when applicable. For multi-step reactions, just give the FINAL product, no intermediates.