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- Relative Intensity 100 80- 40 T 20- 0 MS-IW-0614 25 50 75 100 m/z 125 150 1४ og arbe Day OH OH 175You are trying to come up with a drug to inhibit the activity of an enzyme thought to have a role in liver disease. In the laboratory the enzyme was shown to have a Km of 1.0 x 10-6 M and Vmax of 0.1 micromoles/min.mg measured at room temperature. You developed an uncompetitive inhibitor. In the presence of 5.0 x 10-5 M inhibitor, the apparent Vmax was determined to be 0.02 micromoles/min.mg. What is the Ki of the inhibitor?6) What is the difference between CI-MS and EI-MS? What is CI and EI ?
- ent arch X Aktiv Chemistry ADD FACTOR x( ) 4.82 × 104 10¹2 A laser pulse is 4.82 x 10-2 milliseconds How many nanoseconds is this? 10-⁰ 4.82 x 10-8 10⁰ ns 10 º 4.82 × 10² X Question 30 of 31 4.82 x 10-14 ART ms PeopleSoft session expired 10-12 4.82 x 10-5 10⁰ ANSWER 4.82 x 1016 4.82 x 10-² 4.82 x 101⁰ min 1015 X ? Anthropology and Archaeolo X μs 10³ 4.82 × 10-11 RESET 5 10-3 P 130 70- 60- 50- 40- 30 20 10 0₁ 4000 Ророжа Structue nd, C₂H₂1N 3500 иде Sp 3000 2500 18 +2-20 го- 2000 1800 hu 1600 Ф тро 1400 1200 1000 800 6 Н 6 Н 9 Н 600 УSubject- chemistry
- 10 Wavelength, 1. (nm) E (Red, µ.Mcm- ɛ(Yellow, µMr'cm¬1) Absorbance 500 0.0369 0.000549 0.405 430 0.00506 0.0167 0.474 An orange colored solution is prepared by mixing a red dye solution with a yellow dye solution and the absorbance was measured at the analytical wavelengths of 430 nm and 500 nm. The table provides the molar absorptivity for the red and yellow dye at each analytical wavelength. Calculate the concentration (in u.M) of the red and yellow dye in the mixture. [red] = [yellow] =fill in the missingwhat is the concentration of the unknown sample using serial diluitions: 0.05M 1.7472nm, 0.025M 0.8569nm, 0.0125M 0.4167nm, 0.00625M 0.1958nm the epsilon value is 0.0101 and l is 1 cm
- The students conducted the assay for LDH activity using the two serum samples. Each cuvette (path length 1 cm) contained 3ml of a suitable assay buffer (including pyruvate as substrate). 20 microlitres of either serum was added to the cuvette and the absorbance values immediately recorded at the optimum wavelength for a period of 5 minutes (absorbance readings taken every 30 seconds). Protein concentration of serum sample (mg/ml) Change in absorbance at optimum wavelength per minute Control serum (C) 8 -0.04 Diseased serum (D) 7.8 -0.6 1c. Using the molar absorption coefficient of NADH as 6220 M-1 cm-1, and by application of the Beer-Lambert law, estimate the enzyme activity in the two samples (C and D). Express activity as moles per second. 1d. Estimate the specific activity of the two samples (moles per second per microgram).Molar concentration of the dye stock solution: 2.52e-5 mol/L Operating Wavelength: 630 nm Solutions(Dilutions) Absorbance (A)(a.u.) 1 0.073 2 0.118 3 0.258 4 0.477 Using linear regression determine the absorbance/concentration relationship for the dye. [dye] =_____ x AYou are trying to come up with a drug to inhibit the activity of an enzyme thought to have a role in liver disease. In the laboratory the enzyme was shown to have a Km of 1.0 x 10-6 M and Vmax of 0.1 micromoles/min.mg measured at room temperature. You developed a competitive inhibitor. In the presence of 5.0 x 10-5 M inhibitor, the apparent Km of the enzyme was found to be 1.5 x 10-5 M. What is the Ki of the inhibitor?