Reaction # 1 2 3 4 Reaction 6 acetic acid <-> acetate + H+ malate <-> fumarate + H₂O fructose-6-phosphate <-> glucose- 6-phosphate glucose-1-phosphate <-> glucose- 6-phosphate 5 glucose-6-phosphate + H₂O <- > glucose + phosphate sucrose + H₂O <-> glucose + fructose Keq 0.00002 2.0 140,000 Delta G +0.75 -1.7 -3.3

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The table below shows six reactions, along with either the equilibrium constant
(keq)or the free energy change (Delta G). In each case, decide what will be the
magnitude of the missing parameter. For Keq, decide if it will be greater than or less
than 1. For Delta G, decide if it will be greater than or less than 0. The symbol "<->"
is meant to indicate that the reactions are, in principle, reversible.
Reaction
#
1
2
3
4
Reaction
6
acetic acid <-> acetate + H+
malate <-> fumarate + H₂O
glucose-1-phosphate <-> glucose-
6-phosphate
5 glucose-6-phosphate + H₂O <-
> glucose + phosphate
fructose-6-phosphate <-> glucose- 2.0
6-phosphate
Keq
sucrose + H₂O <-> glucose +
fructose
0.00002
140,000
Delta
G
+0.75
-1.7
-3.3
Transcribed Image Text:The table below shows six reactions, along with either the equilibrium constant (keq)or the free energy change (Delta G). In each case, decide what will be the magnitude of the missing parameter. For Keq, decide if it will be greater than or less than 1. For Delta G, decide if it will be greater than or less than 0. The symbol "<->" is meant to indicate that the reactions are, in principle, reversible. Reaction # 1 2 3 4 Reaction 6 acetic acid <-> acetate + H+ malate <-> fumarate + H₂O glucose-1-phosphate <-> glucose- 6-phosphate 5 glucose-6-phosphate + H₂O <- > glucose + phosphate fructose-6-phosphate <-> glucose- 2.0 6-phosphate Keq sucrose + H₂O <-> glucose + fructose 0.00002 140,000 Delta G +0.75 -1.7 -3.3
Expert Solution
Step 1 Formula

∆G° = - RTlnKeq 

R = 8.314 J K-1 mol-1 

T = 298 K 

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