Free Energy of Hydrolysis (AG) for Liberating an Inorganic Phosphate Molecule AG (kJ/mol) Phosphoenolpyruvate Glucose-1-phosphate Glucose-6-phosphate Glycerol-3-phosphate ATP xicalimi 307.67/04 -61.9 -30.5 -20.9 -12.5 -9.7 AG (Kcal/mol) O Kcaymi 3 Kcal/mol -14.8 -7.3 -5.0 1. Walking consumes about 100 kcal/mi. Given that the molecular weight of ATP is 507.18 g/mole and the reaction that drives muscle contraction is: -3.0 -2.3 ATP + H₂0 → ADP + P₁ How many grams of ATP must be hydrolyzed to walk a mile? Standard free energy = -7.3Kcall mul = 137 mol of ATP (13.7m01) (507.18 g/mol) = 6919.666g of ATP must be hydrom a milo to walk 2. The AG for the reaction Citrate Isocitrate is +6.64 kJ/mol (or +1.59 kcal/mol). The AG for the reaction Isocitrate → a-ketoglutarate is -267 kJ/mol (or -63.9 kcal/mol). What is the AG' value for the for the conversion of Citrate → a-ketoglutarate? AG" = (-267 KJ/moi) - (+ 6.64 k) /mol) = -273.64 kJ/mol 3. Is the above combined reaction exergonic or endergonic? AG is negative so it's a exergonic reaction. 4. A number of organophosphate compounds undergo hydrolysis similar to ATP. Consider the following and predict whether the reaction will proceed in the direction written. Show your calculation for the AGO' for the reaction. ATP + pyruvate phosphoenolpyruvate + ADP Similar to the above question, predict whether the following reaction will proceed in the direction written. Show your calculation for the AGo for the reaction. ATP + glycerol glycerol-3-phosphate + ADP

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### Free Energy of Hydrolysis (ΔG°') for Liberating an Inorganic Phosphate

#### Table of Molecules and Their ΔG°' Values:
- **Phosphoenolpyruvate:** 
  - ΔG°' (kJ/mol): -61.9
  - ΔG°' (kcal/mol): -14.8
- **ATP:** 
  - ΔG°' (kJ/mol): -30.5
  - ΔG°' (kcal/mol): -7.3
- **Glucose 1-phosphate:** 
  - ΔG°' (kJ/mol): -20.9
  - ΔG°' (kcal/mol): -5.0
- **Glucose 6-phosphate:** 
  - ΔG°' (kJ/mol): -13.8
  - ΔG°' (kcal/mol): -3.3
- **Glycerol 3-phosphate:** 
  - ΔG°' (kJ/mol): -9.2
  - ΔG°' (kcal/mol): -2.3

### Problems and Explanations:

1. **ATP Hydrolysis Calculation:**
   - Walking consumes about 100 kcal/mi.
   - Reaction: \( \text{ATP} + \text{H}_2\text{O} \rightarrow \text{ADP} + \text{P}_i \)
   - Molecular weight of ATP: 507.18 g/mole.
   - Standard free energy: -7.3 kcal/mol.

   **Calculation:**
   - 100 kcal/mi ÷ 7.3 kcal/mol = 13.7 mol of ATP.
   - (13.7 mol) × (507.18 g/mol) = 6939.6 g of ATP.
   - Therefore, 693.6 g of ATP must be hydrolyzed to walk a mile.

2. **ΔG°' for Citrate to α-ketoglutarate:**
   - Citrate to Isocitrate ΔG°' = +6.64 kJ/mol (+1.59 kcal/mol).
   - Isocitrate to α-ketoglutarate ΔG°' = -267 kJ/mol (-63.9 kcal/mol).

   **Calculation:**
   - ΔG°' = (-267 k
Transcribed Image Text:### Free Energy of Hydrolysis (ΔG°') for Liberating an Inorganic Phosphate #### Table of Molecules and Their ΔG°' Values: - **Phosphoenolpyruvate:** - ΔG°' (kJ/mol): -61.9 - ΔG°' (kcal/mol): -14.8 - **ATP:** - ΔG°' (kJ/mol): -30.5 - ΔG°' (kcal/mol): -7.3 - **Glucose 1-phosphate:** - ΔG°' (kJ/mol): -20.9 - ΔG°' (kcal/mol): -5.0 - **Glucose 6-phosphate:** - ΔG°' (kJ/mol): -13.8 - ΔG°' (kcal/mol): -3.3 - **Glycerol 3-phosphate:** - ΔG°' (kJ/mol): -9.2 - ΔG°' (kcal/mol): -2.3 ### Problems and Explanations: 1. **ATP Hydrolysis Calculation:** - Walking consumes about 100 kcal/mi. - Reaction: \( \text{ATP} + \text{H}_2\text{O} \rightarrow \text{ADP} + \text{P}_i \) - Molecular weight of ATP: 507.18 g/mole. - Standard free energy: -7.3 kcal/mol. **Calculation:** - 100 kcal/mi ÷ 7.3 kcal/mol = 13.7 mol of ATP. - (13.7 mol) × (507.18 g/mol) = 6939.6 g of ATP. - Therefore, 693.6 g of ATP must be hydrolyzed to walk a mile. 2. **ΔG°' for Citrate to α-ketoglutarate:** - Citrate to Isocitrate ΔG°' = +6.64 kJ/mol (+1.59 kcal/mol). - Isocitrate to α-ketoglutarate ΔG°' = -267 kJ/mol (-63.9 kcal/mol). **Calculation:** - ΔG°' = (-267 k
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