R148 R149 R150 If R148 is 18 Ohms, R149 is 13 Ohms, R150 is 25 Ohms, and there is 4 Amps flowing through R150, what is the current through R148? Please show 3 decimal places and don't include units in your answer (i.e. don't include A in your answer).
R148 R149 R150 If R148 is 18 Ohms, R149 is 13 Ohms, R150 is 25 Ohms, and there is 4 Amps flowing through R150, what is the current through R148? Please show 3 decimal places and don't include units in your answer (i.e. don't include A in your answer).
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question
![**Physics / Electrical Engineering Problem**
**Series-Parallel Circuit Analysis**
**Problem Statement:**
If \( R148 \) is \( 18 \) Ohms, \( R149 \) is \( 13 \) Ohms, \( R150 \) is \( 25 \) Ohms, and there are \( 4 \) Amps flowing through \( R150 \), what is the current through \( R148 \)?
**Instructions:**
Please show 3 decimal places and don't include units in your answer (i.e. don't include \( A \) in your answer).
**Diagram Description:**
There is a circuit diagram featuring three resistors:
1. \( R148 \) is connected in series at the top.
2. \( R149 \) and \( R150 \) are connected in parallel to each other directly beneath \( R148 \).
\[
\text{ R148}
\begin{cases}
18 \Omega \quad
\end{cases}
\]
\[
\text{ R149}
\begin{cases}
13 \Omega \quad
\end{cases}
\]
\[
\text{ R150}
\begin{cases}
25 \Omega \quad
\end{cases}
\]
---
**Answer Input Box:**
\[ \boxed{} \]
**Please Enter Your Answer in the Box Provided.**](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F17885dbd-a017-4754-b4be-f0580293856f%2Fe648395e-3728-499e-8d95-0af1cb17446d%2Fjcee4if_processed.png&w=3840&q=75)
Transcribed Image Text:**Physics / Electrical Engineering Problem**
**Series-Parallel Circuit Analysis**
**Problem Statement:**
If \( R148 \) is \( 18 \) Ohms, \( R149 \) is \( 13 \) Ohms, \( R150 \) is \( 25 \) Ohms, and there are \( 4 \) Amps flowing through \( R150 \), what is the current through \( R148 \)?
**Instructions:**
Please show 3 decimal places and don't include units in your answer (i.e. don't include \( A \) in your answer).
**Diagram Description:**
There is a circuit diagram featuring three resistors:
1. \( R148 \) is connected in series at the top.
2. \( R149 \) and \( R150 \) are connected in parallel to each other directly beneath \( R148 \).
\[
\text{ R148}
\begin{cases}
18 \Omega \quad
\end{cases}
\]
\[
\text{ R149}
\begin{cases}
13 \Omega \quad
\end{cases}
\]
\[
\text{ R150}
\begin{cases}
25 \Omega \quad
\end{cases}
\]
---
**Answer Input Box:**
\[ \boxed{} \]
**Please Enter Your Answer in the Box Provided.**
![### Electrical Circuit Analysis
**Problem Statement:**
Refer to the given circuit diagram with resistors R148, R149, and R150:
- \(R148\) is 46 Ohms
- \(R149\) is 25 Ohms
- \(R150\) is 14 Ohms
Given that there is a current of 3 Amps flowing through \(R148\), calculate the current through \(R150\).
**Detailed Solution:**
To solve this problem, we first analyze the circuit configuration shown in the diagram:
1. **Description of the Circuit Diagram:**
- The circuit is composed of three resistors: \(R148\), \(R149\), and \(R150\).
- Resistor \(R148\) is in series with a parallel combination of \(R149\) and \(R150\).
2. **Equivalent Resistance:**
- Calculate the equivalent resistance of \(R149\) and \(R150\) which are in parallel:
\[
\frac{1}{R_{parallel}} = \frac{1}{R149} + \frac{1}{R150}
\]
\[
\frac{1}{R_{parallel}} = \frac{1}{25\ \Omega} + \frac{1}{14\ \Omega}
\]
\[
\frac{1}{R_{parallel}} = 0.04 + 0.071428571
\]
\[
\frac{1}{R_{parallel}} \approx 0.111428571
\]
\[
R_{parallel} \approx \frac{1}{0.111428571} \approx 8.97\ \Omega
\]
- The total resistance in the circuit (\(R_{total}\)) is the sum of \(R148\) and \(R_{parallel}\):
\[
R_{total} = 46\ \Omega + 8.97\ \Omega
\]
\[
R_{total} \approx 54.97\ \Omega
\]
3. **Total Voltage (V):**
- Using Ohm's law, calculate the total voltage across the circuit:
\[
V = I \times R_{total}
\]
\[
V = 3\ \text{Am](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F17885dbd-a017-4754-b4be-f0580293856f%2Fe648395e-3728-499e-8d95-0af1cb17446d%2F90ge3s9_processed.png&w=3840&q=75)
Transcribed Image Text:### Electrical Circuit Analysis
**Problem Statement:**
Refer to the given circuit diagram with resistors R148, R149, and R150:
- \(R148\) is 46 Ohms
- \(R149\) is 25 Ohms
- \(R150\) is 14 Ohms
Given that there is a current of 3 Amps flowing through \(R148\), calculate the current through \(R150\).
**Detailed Solution:**
To solve this problem, we first analyze the circuit configuration shown in the diagram:
1. **Description of the Circuit Diagram:**
- The circuit is composed of three resistors: \(R148\), \(R149\), and \(R150\).
- Resistor \(R148\) is in series with a parallel combination of \(R149\) and \(R150\).
2. **Equivalent Resistance:**
- Calculate the equivalent resistance of \(R149\) and \(R150\) which are in parallel:
\[
\frac{1}{R_{parallel}} = \frac{1}{R149} + \frac{1}{R150}
\]
\[
\frac{1}{R_{parallel}} = \frac{1}{25\ \Omega} + \frac{1}{14\ \Omega}
\]
\[
\frac{1}{R_{parallel}} = 0.04 + 0.071428571
\]
\[
\frac{1}{R_{parallel}} \approx 0.111428571
\]
\[
R_{parallel} \approx \frac{1}{0.111428571} \approx 8.97\ \Omega
\]
- The total resistance in the circuit (\(R_{total}\)) is the sum of \(R148\) and \(R_{parallel}\):
\[
R_{total} = 46\ \Omega + 8.97\ \Omega
\]
\[
R_{total} \approx 54.97\ \Omega
\]
3. **Total Voltage (V):**
- Using Ohm's law, calculate the total voltage across the circuit:
\[
V = I \times R_{total}
\]
\[
V = 3\ \text{Am
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