To a measurement range of -4 to 6 V, apply a 4-bit analog-to-digital converter. a- Identify the assigned voltages to each of the bins. b- Determine the voltage that will be assigned to a measurement reading -3.25 V. Calculate the percentage ADC error. c- Determine the voltage that will be assigned to a measurement reading 4.11 V. Calculate the percentage ADC error.

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I posted this twice, and got even more confused because the answers were different. Can anyone please tell me how to do it right?

To a measurement range of -4 to 6 V, apply a 4-bit analog-to-digital converter. 

a- Identify the assigned voltages to each of the bins.

b- Determine the voltage that will be assigned to a measurement reading -3.25 V. Calculate the percentage ADC error.

c- Determine the voltage that will be assigned to a measurement reading 4.11 V. Calculate the percentage ADC error.

Expert Solution
Step 1

In given problem

ADC is 4 bit hence

number of steps(bins) in which analog input is divided is

2n =24=16 stepsi.e.1 to 16   or 0 to 15

Step 2

Input voltage range is from negative to positive voltage

for ADC, input total input voltage range that need to covert in digital is

-4 V to +6 V

                                       resolution =Input range2n-1                   =6-(-4)24-1                  =1015=0.67 V

this means ADC will convert analog input to digital in a step of 0.66 V. 

total steps are 16  that is from 0 to15

Step 3
         STEP (bins)    BINARY OUTPUT   ANALOG INPUT
0    0000   -4 +0 =-4 V
1 0001 -4+0.67 =-3.33 V
2 0010    -3.33 V+0.67 =-2.66 V
3 0011          -2.66 +0.67 =- 1.99 V
4 0100      -1.99 +0.67  =- 1.32 V
5 0101 -1.32+0.67=- 0.65 V
6 0110 -0.65+0.67=- 0.02 V
7 0111 -0.02+0.67=0.69 V
8 1000 0.69+0.67 =1.36 V

 

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