Question 2: The composite beam consists of a wood core and two plates of steel. If the allowable bending stress for the wood is (allow)=20MPa and for the steel (allow)t =130MPa determine the maximum moment that can be applied to the beam. E₁ =11GPa, E., = 200GPa Take: z A mm A = 130 mm B= 80 mm M 20 mm 20 mm- B mm

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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Question 2 :
The composite beam consists of a wood core and two plates of steel. If the allowable bending
stress for the wood is (allow)w = 20MPa and for the steel (allow)st = 130MPa
determine the maximum moment that can be applied to the beam.
E = 11GPa, Et = 200GPa
Take:
A mm
A = 130 mm
B = 80 mm
M
20 mm
20 mm-
B mm
Solution :
200(10³) = 18.182
11(10⁹)
Page 1
n =
E
The width of steel must be increased to an equivalent width for wood:
W..
=
mm
1
-width (A³)=
(10³) m
12
Est
=
Transcribed Image Text:Question 2 : The composite beam consists of a wood core and two plates of steel. If the allowable bending stress for the wood is (allow)w = 20MPa and for the steel (allow)st = 130MPa determine the maximum moment that can be applied to the beam. E = 11GPa, Et = 200GPa Take: A mm A = 130 mm B = 80 mm M 20 mm 20 mm- B mm Solution : 200(10³) = 18.182 11(10⁹) Page 1 n = E The width of steel must be increased to an equivalent width for wood: W.. = mm 1 -width (A³)= (10³) m 12 Est =
Failure of wood:
Mc
(₁) max
=
I
20(106)= 0.5 MA
I
Failure of steel:
(0:1) max
130(106)=
M=
nMc
I
(18.182) (0.5MA).
I
kNm
M =
kNm
Ans
Transcribed Image Text:Failure of wood: Mc (₁) max = I 20(106)= 0.5 MA I Failure of steel: (0:1) max 130(106)= M= nMc I (18.182) (0.5MA). I kNm M = kNm Ans
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