Question 2) For a shallow foundation shown below: A. Estimate the ultimate bearing capacity when the water table located at a depth of 2 m below the ground surface. B. Estimate the moments about the x- and y-axis; assume that the foundation is subjected to a vertical load and a moment. If eß and e is 0.33 m and 0.12 m, respectively. G.S 2 m (2 m x 3 m) Silty clay Yd=17 kN/m³, Ysat = 20 kN/m³ Cs Scanned with CamScanner c'=78 kN/m² '=35° Shear modulus=250 kN/m² 6 m

Question 2) For a shallow foundation shown below: A. Estimate the ultimate bearing capacity when the water table located at a depth of 2 m below the ground surface. B. Estimate the moments about the x- and y-axis; assume that the foundation is subjected to a vertical load and a moment. If eß and e is 0.33 m and 0.12 m, respectively. G.S 2 m (2 m x 3 m) Silty clay Yd=17 kN/m³, Ysat = 20 kN/m³ Cs Scanned with CamScanner c'=78 kN/m² '=35° Shear modulus=250 kN/m² 6 m

Principles of Foundation Engineering (MindTap Course List)

9th Edition

ISBN:9781337705028

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter9: Settlement Of Shallow Foundations

Section: Chapter Questions

Problem 9.15P

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Load and resistance factor design

Load and resistance factors design (LRFD), also known as Limit state design (LSD), refers to the design method used in building engineering. A boundary condition is a condition of a structure where it can no longer meet the relevant design requirements. The condition may refer to the load level or other actions on the structure, while the terms refer to the integrity of the structure, suitability for use, durability, or other design requirements. A structure designed for LRFD is limited to keeping track of all possible actions during its design time and is always ready for use, with the appropriate level of reliability in each boundary condition. LRFD-based construction codes clearly define the appropriate levels of reliability in their instructions.

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Question 1) For a shallow foundation measuring (1.7 m x 2.2 m) as shown below: , A. Estimate the elastic settlement proposed by Mayerhof. Then, B. Estimate the elastic settlement proposed by Bowles, if the water table rises 1.5 m. Then, Use yw=10 kN/m³ qnet= 1.2 MN/m2 G.S 1.5 m Sand Yd=16 kN/m³ Ysat= 17 kN/m3 %3D 2.5 m N60=52 V W.T. Silty Sand Ya=18 kN/m³ Ysat = 18.5 kN/m? N60=52 3.5 m Sand Ya=19 kN/m3 Ysat = 22 kN/m³ e, = 0.4, Ae=0.04 , o'= 194 kN/m2 5 m Cc= 0.3, Cs= 0.2 , Ca= 0.05 N60=60 CS Scanned with CamScanner
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