QUESTION #2 A rectangular foundation (B x 1.2B) has to be constructed as shown in Figure. Assume that y-17 kN/m³, Ysat = 20 kN/m³, D1-300, D2-340, Dr 2 m, and Dw = 1 m. The gross allowable load with FS = 4 is 750 kN. Determine the size of the foundation by using general bearing capacity equation. Use: Meyerhof's bearing capacity and depth factors, DeBeer's shape factors. Qall 1.0 m 1.0 m G.W.L B x 1.2B Y = 17.0 kN/m³ c=0 = 30° Ysat = 20.0 kN/m² c = 0 kN/m² $2= 34°

QUESTION #2 A rectangular foundation (B x 1.2B) has to be constructed as shown in Figure. Assume that y-17 kN/m³, Ysat = 20 kN/m³, D1-300, D2-340, Dr 2 m, and Dw = 1 m. The gross allowable load with FS = 4 is 750 kN. Determine the size of the foundation by using general bearing capacity equation. Use: Meyerhof's bearing capacity and depth factors, DeBeer's shape factors. Qall 1.0 m 1.0 m G.W.L B x 1.2B Y = 17.0 kN/m³ c=0 = 30° Ysat = 20.0 kN/m² c = 0 kN/m² $2= 34°

Principles of Foundation Engineering (MindTap Course List)

9th Edition

ISBN:9781337705028

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter9: Settlement Of Shallow Foundations

Section: Chapter Questions

Problem 9.15P

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Load and resistance factor design

Load and resistance factors design (LRFD), also known as Limit state design (LSD), refers to the design method used in building engineering. A boundary condition is a condition of a structure where it can no longer meet the relevant design requirements. The condition may refer to the load level or other actions on the structure, while the terms refer to the integrity of the structure, suitability for use, durability, or other design requirements. A structure designed for LRFD is limited to keeping track of all possible actions during its design time and is always ready for use, with the appropriate level of reliability in each boundary condition. LRFD-based construction codes clearly define the appropriate levels of reliability in their instructions.

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Question 2) For a shallow foundation shown below: A. Estimate the ultimate bearing capacity when the water table located at a depth of 2 m below the ground surface. B. Estimate the moments about the x- and y-axis; assume that the foundation is subjected to a vertical load and a moment. If eg and eL is 0.33 m and 0.12 m, respectively. G.S Iz 2 m (2 m x 3 m) Silty clay Yo=17 kN/m³ , Ysat = 20 kN/m3 %3D 6 m c'=78 kN/m? 0'=35° Shear modulus=250 kN/m? CS Scanned with CamScanner
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A column foundation is 3 m × 2 m in plan. Given: Df = 1.5 m, p' = 30°, c' = 80 kN/m². Using the general bearing capacity equation (CFEM - see class slides from March 17 - similar to Example 1 and 2 but with an added capacity term related to cohesion) and = 0.5, determine the factored bearing capacity of the foundation (i.e. – use Þ). Use Yw = 9.81 kN/m³. For simplicity, read the values of Nc, N₁, and Ny directly from the table on page 26 of the lecture slides - use the highlighted columns. Also, determine the maximum factored load for the column. 1.5 m 1 m 3m x 2m y = 17 kN/m³ Groundwater level Ysat 19.5 kN/m³ =
QUESTION 5 A 1.8 m x 2.5 m foundation is shown in Figure. If the load eccentricity B 0.45 m and e 0.30 (two-way), determine the allowable load Qall. = 1.6 m ↑ B x L = 1.8 m x 2.5 m c = 0 kN/m² = 34° = 18 kN/m³ Yn Gs = 3
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A square shallow foundation (B × B) is planned to be constructed on a normality consolidated (NC) clay soil as shown in the below figure. The maximum acceptable settlement for the foundation is equal to 2.0 inches (5 cm), and the safety factor against bearing capacity is FS = 4. Determine the size of foundation. (Note: To simplify the calculations, ignore both the elastic settlement and secondary compression settlement. Also consider Ao'ave = 4o'm) Q = 500 kN Ysat = 19.24 kN/m³ eo = 0.8 C. = 0.25 p'= 0 c' = 25 kPa FS again Bearing Capacity = 4 Acceptable settlement = 2.0 inches 2 m В ХВ 10 m
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