Question 2) For a shallow foundation shown below: A. Estimate the ultimate bearing capacity when the water table located at a depth of 2 m below the ground surface. B. Estimate the moments about the x- and y-axis; assume that the foundation is subjected to a vertical load and a moment. If eß and e is 0.33 m and 0.12 m, respectively. G.S 2 m (2 m x 3 m) Silty clay Yd=17 kN/m³, Ysat = 20 kN/m³ Cs Scanned with CamScanner c'=78 kN/m² '=35° Shear modulus=250 kN/m² 6 m

Q: Consider the strip footing shown in the figure below.  The soil consists of sand with ’ =30° and…

A: For strip footing:qu = cNc + qNq + 0.5γBNγ For Nq:Nq = 22.46 For Nγ:Nγ = 19.16 For strip footing…

Q: A square foundation must withstand an allowable load of 1805 kN with reliability of 3. With the…

A:

Q: A footing with 2x5 m is founded at a depth of 1 m in a stiff clay of saturated unit weight 19 kN/m³,…

A: Saturated unit weight= 19 KN/m3  Depth of footing= 1 m  Su= 105 Kpa Footing = 2*5 m

Q: 2 ft 24 ft 24 ft 24 ft 2 ft Problem 4 B E F G 3 ft DL=190 kip DL-100 kip DL=180 kip LL = 60 kip LL=…

A: Given data: Size of the mat = 76 ft by 96 ft Column size = 24 in. by 24 in. qall(net)=1.5 kip/ft2…

Q: A square foundation is placed at a depth of 1.5 m within a sandy clay where c'=14k/m2 , phi'=23 and…

A: Compaction is the process in which soil gets distributed properly and its quantity gets pressured by…

Q: A 4.5 m square foundation exerts a uniform pressure of 200kN/m2 on soil. Determine; i. The vertical…

A:

Q: Explain the attached problem

A: Bf = 1.2m Df = 1m γ = 15.5 KN/m3ϕ = 35°c' = 0

Q: 5.2 A square column foundation has to carry a gross allowable load of 1805 kN (FS = 3). Given: D,=…

A:

Q: 3,500 kN/m2; and µs = 0.35. (Useful formula and table can be found from Appendix)

A: 5 images are attached to solve the following question

Q: Consider a rectangular footing and loading conditions shown in the figure below. The foundation…

A: Foundation rests on the ground.Load= 300 kNMoment about y axis = 400 kNweight of the footing - 450…

Q: A footing with 2×5 m is founded at a depth of 1 m in a stiff clay of saturated unit weight 19 kN/m³,…

A: Saturated unit weight= 19 KN/m3  Depth of footing= 1 m

Q: b. Ultimate soil bearing capacity, qu (in kN/m2) qu = c. Allowable soil bearing capacity, qall (in…

A: γ = 17 Knm3ϕ = 36°c' = 10 KNm2Df = 1.5mB = 1.25m

Q: A foundation is constructed in a soil with the following parameters: c' = 5.0kN/m? y = 18.5 kN/m³ Ø'…

A: The given data is: B=2 m L=3 m C'=5 KN/m2 Q=3000 KN M=300 KN-m calculating eccentricity:…

Q: A square foundation must withstand an allowable load of 1805 kN reliability of 3. With the given…

A:

Q: A rigid shallow foundation 4 m 2m. Calculate the elastic settlement at the center of the foundation.…

A: Step 1

Q: Problem #3 lo lag An eccentrically loaded continuous foundation is shown in (Eccentricity in one…

A:

Q: A mat foundation is in plan 40 m x 40 m with a thickness of 1.2 m. The total column and bearing wall…

A: ASKED: To compute the average gross bearing pressure and the average net bearing pressure for the…

Load and resistance factor design

Load and resistance factors design (LRFD), also known as Limit state design (LSD), refers to the design method used in building engineering. A boundary condition is a condition of a structure where it can no longer meet the relevant design requirements. The condition may refer to the load level or other actions on the structure, while the terms refer to the integrity of the structure, suitability for use, durability, or other design requirements. A structure designed for LRFD is limited to keeping track of all possible actions during its design time and is always ready for use, with the appropriate level of reliability in each boundary condition. LRFD-based construction codes clearly define the appropriate levels of reliability in their instructions.