A column foundation (Figure 1) is 3 m x 2 m in plane. Given: D,= 2m, þ=25°, c = 50 kN/m?. Using the general bearing capacity equation and FS = 4, determine the net allowable load the foundation could carry (Use this equation for the net allowable bearing cacpcity: 9all(net) %3D FS Figure 1 Yso = 16.8 N/m 1m W.T D, = 2m Figure 1 3m x2m a15 Yso = 16.8 N/m 1m W.T . Solve Problem 3 if the vertical load is inclined with a = 15° D, = 2m 3m x2m
A column foundation (Figure 1) is 3 m x 2 m in plane. Given: D,= 2m, þ=25°, c = 50 kN/m?. Using the general bearing capacity equation and FS = 4, determine the net allowable load the foundation could carry (Use this equation for the net allowable bearing cacpcity: 9all(net) %3D FS Figure 1 Yso = 16.8 N/m 1m W.T D, = 2m Figure 1 3m x2m a15 Yso = 16.8 N/m 1m W.T . Solve Problem 3 if the vertical load is inclined with a = 15° D, = 2m 3m x2m
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Solve question 4
![3. A column foundation (Figure 1) is 3 m x 2 m in plane. Given: D= 2m, 0=25°, c = 50 kN/m². Using the
general bearing capacity equation and FS = 4, determine the net allowable load the foundation could
carry (Use this equation for the net allowable bearing cacpcity: qall(net)
qu-4).
FS
Figure 1
Yso = 16.8 N/m
1m
W.T
D, = 2m
Figure 1
3m x2m
15
Ysoil = 16.8 N/m
1 m
W.T
4. Solve Problem 3 if the vertical load is inclined with a = 15°
D, = 2m
3m x2m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff49f1295-8cf6-4b25-aafa-282cb35e3758%2Fdbbafb2b-128e-43e4-8ce9-a7cc75815737%2Fc3cmqtj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3. A column foundation (Figure 1) is 3 m x 2 m in plane. Given: D= 2m, 0=25°, c = 50 kN/m². Using the
general bearing capacity equation and FS = 4, determine the net allowable load the foundation could
carry (Use this equation for the net allowable bearing cacpcity: qall(net)
qu-4).
FS
Figure 1
Yso = 16.8 N/m
1m
W.T
D, = 2m
Figure 1
3m x2m
15
Ysoil = 16.8 N/m
1 m
W.T
4. Solve Problem 3 if the vertical load is inclined with a = 15°
D, = 2m
3m x2m
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