A column foundation is 3 m × 2 m in plan. Given: Df = 1.5 m, p' = 30°, c' = 80 kN/m².Using the general bearing capacity equation (CFEM - see class slides from March 17 -similar to Example 1 and 2 but with an added capacity term related to cohesion) and =0.5, determine the factored bearing capacity of the foundation (i.e. – use Þ). Use Yw =9.81 kN/m³. For simplicity, read the values of Nc, N₁, and Ny directly from the table on page26 of the lecture slides - use the highlighted columns. Also, determine the maximumfactored load for the column.1.5 m1 m3m x 2my = 17 kN/m³Groundwater levelYsat 19.5 kN/m³=

Foundation: L = 3m B = 2 m Depth of the footing, Df = 1.5 m The angle of internal friction, ϕ=30o…

A column foundation is 3 m × 2 m in plan. Given: Df = 1.5 m, ' = 30°, c' = 80 kN/m². Using the general bearing capacity equation (CFEM - see class slides from March 17 - similar to Example 1 and 2 but with an added capacity term related to cohesion) and = 0.5, determine the factored bearing capacity of the foundation (i.e. - use ). Use Yw = 9.81 kN/m³. For simplicity, read the values of Nc, Nq, and Ny directly from the table on page 26 of the lecture slides - use the highlighted columns. Also, determine the maximum factored load for the column. 1.5 m 1 m 3 mx 2 m y = 17 kN/m³ Groundwater level Ysat = 19.5 kN/m³

A column foundation is 3 m × 2 m in plan. Given: Df = 1.5 m, ' = 30°, c' = 80 kN/m². Using the general bearing capacity equation (CFEM - see class slides from March 17 - similar to Example 1 and 2 but with an added capacity term related to cohesion) and = 0.5, determine the factored bearing capacity of the foundation (i.e. - use ). Use Yw = 9.81 kN/m³. For simplicity, read the values of Nc, Nq, and Ny directly from the table on page 26 of the lecture slides - use the highlighted columns. Also, determine the maximum factored load for the column. 1.5 m 1 m 3 mx 2 m y = 17 kN/m³ Groundwater level Ysat = 19.5 kN/m³

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Load and resistance factor design

Load and resistance factors design (LRFD), also known as Limit state design (LSD), refers to the design method used in building engineering. A boundary condition is a condition of a structure where it can no longer meet the relevant design requirements. The condition may refer to the load level or other actions on the structure, while the terms refer to the integrity of the structure, suitability for use, durability, or other design requirements. A structure designed for LRFD is limited to keeping track of all possible actions during its design time and is always ready for use, with the appropriate level of reliability in each boundary condition. LRFD-based construction codes clearly define the appropriate levels of reliability in their instructions.

Question

A column foundation is 3 m × 2 m in plan. Given: Df = 1.5 m, p' = 30°, c' = 80 kN/m².
Using the general bearing capacity equation (CFEM - see class slides from March 17 -
similar to Example 1 and 2 but with an added capacity term related to cohesion) and =
0.5, determine the factored bearing capacity of the foundation (i.e. – use Þ). Use Yw =
9.81 kN/m³. For simplicity, read the values of Nc, N₁, and Ny directly from the table on page
26 of the lecture slides - use the highlighted columns. Also, determine the maximum
factored load for the column.
1.5 m
1 m
3m x 2m
y = 17 kN/m³
Groundwater level
Ysat 19.5 kN/m³
=

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