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Principles of Foundation Engineering (MindTap Course List)
8th Edition
ISBN: 9781305081550
Author: Braja M. Das
Publisher: Cengage Learning
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Textbook Question
Chapter 7, Problem 7.9P
Solve Problem 7.8 using Eq. (7.29). Ignore the post-construction settlement.
7.8 Solve Problem 7.4 with Eq. (7.20). Ignore the correction factor for creep. For the unit weight of soil, use γ = 115 lb/ft3.
7.4 Figure 7.3 shows a foundation of 10 ft × 6.25 ft resting on a sand deposit. The net load per unit area at the level of the foundation, qo, is 3000 lb/ft2. For the sand, μs = 0.3, Es = 3200 lb/in.2, Df = 2.5 ft, and H = 32 ft. Assume that the foundation is rigid and determine the elastic settlement the foundation would undergo. Use Eqs. (7.4) and (7.12).
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Students have asked these similar questions
6.8 Refer to Figure P6.8. Using the procedure outlined in Section 6.8, determine the
average stress increase in the clay layer below the center of the foundation due to the
net foundation load of 50 ton. [Use Eq. (6.28).]
4:5 ft
3 ft
50 ton (net load)
10 ft
5 ft x 5 ft
Sand
y=100 lb/ft!
Sand
Yat=122 lb/ft³
Groundwater
table
Ysat ⇒120 lb/ft³
= 0.7
C=0.25
-C, 0,06
Preconsolidation pressure = 2000 lb/ft²
Figure P6.8
7.14 Refer to Figure 7.15. For a foundation on a layer of sand, given: B = 5 ft, L = 10 ft,
d = 5 ft, B = 26.6°, e = 0.5 ft, and & = 10°. The Pressuremeter testing at the site pro-
duced a mean Pressuremeter curve for which the pam) versus AR/R, points are as follow.
AR/R.
(1)
P,(m) (lb/in.?)
(2)
0.002
7.2
0.004
24.2
0.008
32.6
0.012
42.4
0.024
68.9
0.05
126.1
0.08
177.65
0.1
210.5
0.2
369.6
What should be the magnitude of Q, for a settlement (center) of 1 in.?
Foundation
BxL
В
Figure 7.15 Definition of parameters-B,
Problem 1. A column foundation (Figure below) is 3 m × 2 m in plan. The load on the column,
including the weight of the foundation is 4500 kN. Determin the average vertical stress increase 4
m beneath the corner of the foundation in the soil layer due to the foundation loading by:
a) Boussinesq equations
b) 2:1 method
Given: Df = 1.5 m, Ø'= 25°, c'= 70 kN/m².
1.5 m 1 m
3m x 2m
y = 17 kN/m³
Water level
Ysat 19.5 kN/m³
Chapter 7 Solutions
Principles of Foundation Engineering (MindTap Course List)
Ch. 7 - Prob. 7.1PCh. 7 - A planned flexible load area (see Figure P7.2) is...Ch. 7 - Prob. 7.3PCh. 7 - Prob. 7.4PCh. 7 - Prob. 7.5PCh. 7 - Prob. 7.6PCh. 7 - Prob. 7.7PCh. 7 - Prob. 7.8PCh. 7 - Solve Problem 7.8 using Eq. (7.29). Ignore the...Ch. 7 - A continuous foundation on a deposit of sand layer...
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- FIGURE P8.9 square foundation, 15 m wide, carries a net column load of 500 kN as shown in Figure P8.11. Determine the average stress increaso beneath the center of the foundation in the clay layer. a. Using Eq. (8.25), b. Using Eqs. (8.26) and (8.10), and c. Using Eqs (8.26) and (8. 15). 8.11 A 500 KN (net load) Sand 0.9 m Clay 3 marrow_forwardd 8.16 An irregularly shaped footing shown in the figure is loaded with 60 kN/m² uniform load on the ground. Compute the vertical stress increment under Point A at the depth z = 4 m. INTRODUC INT 5.0 m 5.0 m 15.0 m A 5.0 m r = 5.0 marrow_forwardRefer to Figure P6.8. Using the procedure outlined in Section 6.8, determine the average stress increase in the clay layer below the center of the foundation due to the net foundation load of 50 ton.arrow_forward
- Problem (4.10): The foundation plan shown in the figure below is subjected to a uniform contact pressure of 40 kN/m². Determine the vertical stress increment due to the foundation load at (5m) depth below the point (x). →|1.5m + 1.5m 2m 3 0.5m 2m + 3m 3m 3marrow_forward7.7 78 Eq. (7.43) and μ, = 0. Refer to Figure P7.7. Using the procedure outlined in Section 7.10, determine the average stress increase in the clay layer below the center of the foundation due to the net foundation load of 445 kN. [Use Eq. (7.26).] Figusa M70arrow_forwardG1 PLEASE HELParrow_forward
- Q3c. The soil profile at a new construction site for a shallow foundation is shown in Figure Q3. Prior to construction, a uniformly distributed load of 120 kN/m² is applied to the surface of the soil. By using C, equal to 0.133C. Sand Y = 14 kN/m? 3m Ground water table 3m Ysat = 18 kN/m Sand Ysat = 19 kN/m? Void ratio e = 0.8 3m Clay LL = 40 Sand Figure Q3 (i) Calculate the settlement of the clay layer caused by primary consolidation if the clay is normally consolidated. (ii) Calculate the settlement of the clay layer caused by primary consolidation if the preconsolidation pressure (o'.) = 170 kN/m².arrow_forwardFigure Q1 shows two parallel strip footings 3m wide and 5m apart (measured from centre to centre), which transmit a compressive pressure of 200kN/m² and 100KN/m respectively. Determine the increment of total vertical stress at points A and B, located 3m below the ground. 1. q=200 kPa q=100 kPa 3;m 3.m 5 m 3 m A+ B+ Figure Q1arrow_forwardA butt weld is set on the cross section of an I-shaped beam. The re are bending moment M ard sheao forne V at the speicing position, where Ma || 20 KN m and v 374KN The beam is made of Q355 b steel and semi- automatic weld is used with welding rod E50. The des ign value of the weld tensile to Strength f" is 260 N/mnm?. c heek whethe please The stregth of the butt weld is safe by eloulation. ET 3.arrow_forward
- A rectangular footing 6 m x 3 m carries a uniform pressure of 300 kN/m² on the surface of a soil mass. Determine the vertical stress increase at a depth of 5 m below the surface on the centerline 1.0 m inside the long edge of the foundation. a. 62.17 kPa b. 54.67 kPa C. 81.35 kPa d. 88.88 kPa e 74.16 kPaarrow_forwardindicate the final answer in 3 decimal places.arrow_forwardA square column foundation with base of 1.35 m is shown in the figure. It carries an axial load of 488 kN and has its bottom resting on the ground water table located h1 = 1.4 m. below the ground surface. h2 = 0.9 m and h3 = 2.6 m. Compute the average increase in pressure in KPa in the clay layer below the center of foundation using the 2:1 method. |P Dry Sand h1 Wet Sand Clay h3 Soil Properties: Unit Weight of Dry Sand = 15.8 KN/m3 Saturated Unit Weight of Sand = 19.1 KN/m3 Saturated Unit Weight of Clay = 18.7 KN/m3 Compression Index = 0.264 Swell Index = 1/5Cc *arrow_forward
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