Principles of Foundation Engineering (MindTap Course List)
8th Edition
ISBN: 9781305081550
Author: Braja M. Das
Publisher: Cengage Learning
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11.1
A vertical column load, P = 600 kN, is applied to a rigid concrete foundation
with dimensions B = 1 m and L = 2 m, as shown in Figure 11.45. The founda-
tion rests at a depth D₁ = 0.75 m on a uniform dense sand with the following
properties: average modulus of elasticity, E¸ 20,600 kN/m², and Poisson's
ratio, μ = 0.3. Estimate the elastic settlement due to the net applied pressure,
Ao, on the foundation. Given: H = 5 m.
Foundation
BXL
Figure 11.45
600 KN
V
74
Ao
Soil
Ms = 0.3
Es = 20, 600 kN/m²
Rock
=
0.75 m
5.0 m
A rigid foundation is subjected to a vertical column load, P = 355 kN, as shown
in Figure 11.43. Estimate the elastic settlement due to the net applied pressure,
Ao, on the foundation. Given: B = 2 m; L = 3 m; D, = 1.5 m; H = 4 m; E, =
13,500 kN/m²; and µ, = 0.4.
Foundation
Δσ
D
BX L
Soil
Poisson's ratio
E, = modulus of elasticity H
%3D
Rock
O Cengage Leaming 2014
A circular foundation (D = 6 m) is built on a construction site where the soil profile is shown in Figure 5 below. The
circular foundation applies a uniform pressure of 80 kPa to the surface of clay. The properties of the clay are:
Specific gravity, G₁
Saturated unit weight at
Compression index Ce
Recompression index Cr
Consolidation coefficient, c
Over-consolidation ratio, OCR
10 m
6m Ø
Clay
Impervious rock
Figure 5
2.6
20 kN/m³
0.25
0.10
2.5 m²/year
1.2
(b) Calculate the stress increase at the center of the clay layer and 1) beneath the foundation center and 2) beneath the
edge of the foundation;
(c) Calculate the consolidation settlement beneath the center of the foundation due to the stress increase;
(d) Determine the settlement at the center of the clay after 1 year of applying the pressure;
(e) A 50 mm thick clay sample was taken from the site and consolidated in the oedometer, how long it will take for the
clay to reach 90% consolidation?
Chapter 7 Solutions
Principles of Foundation Engineering (MindTap Course List)
Ch. 7 - Prob. 7.1PCh. 7 - A planned flexible load area (see Figure P7.2) is...Ch. 7 - Prob. 7.3PCh. 7 - Prob. 7.4PCh. 7 - Prob. 7.5PCh. 7 - Prob. 7.6PCh. 7 - Prob. 7.7PCh. 7 - Prob. 7.8PCh. 7 - Solve Problem 7.8 using Eq. (7.29). Ignore the...Ch. 7 - A continuous foundation on a deposit of sand layer...
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Similar questions
- 8.4 A rectangular foundation is shown in Figure P8.2, given B= 2 m, L=4m q=240 kN/m², H=6m, and D; =2 m. (a) Assuming E = 3800KN/m², calculate the average elastic settlement. Use Eq. (8.24). (b) If the clay is normally consolidated, calculate the consolidation settlement. Use Eq. (8.35) and yat = 17.5 kN/m², C¸ = 0.12, and e, = 1.1.arrow_forward8.4 A rectangular foundation is shown in Figure P8.2, given B=2m, L=4m q = 240 kN/m², H = 6m, and D; = 2 m. (a) Assuming E = 3800KN/m², calculate the average elastic settlement. Use Eq. (8.24). (b) If the clay is normally consolidated, calculate the consolidation settlement. Use Eq. (8.35) and y,t = 17.5 kN/m’, C, = 0.12, and e, = 1.1. %3D G.W.T. D,=2 m = 240 kN/m² Clay e. = .IO H= 6 m 1. Rock Figure P8.2 S,(average) = µ,M0 qB (v = 0.5) E (8.24) (8.35)arrow_forwardPlease answer the following question with a step by step solution so I can follow and understand, explain theoryarrow_forward
- Problem 2. Determine the average (top, middle, and bottom) stress increase in the clay layer below the center of foundation due to foundation load of 50 tons. 50 ton (net load) Sand 100 Ib/ 4:5 t Groupdwater table 5 ft X 5 ft *Sand 122 lb/ft 3 ft A120 Ib/ft 0.7 C, = 0.25 10 ft 0,06 Preconsolidation pressure = 2000 lb/ft?arrow_forwardsubject: Geotechnical Engineeringbook: principle of foundation engineering - Braja M Dasarrow_forwardPlease explain the probelm step by step so I can understand the theory and concept. Please show clear calculations and clear solutions so I can understand, thank youarrow_forward
- A normally consolidated clay layer 4.91 m. thick has a void ratio of 1.12. Liquid limit is equal to 35 and the average effective stress on the clay layer was 81 kPa. The average stress on it is increased to 125 kPa. as result of the construction of a foundation. If the clay layer is preconsolidated, compute the consolidation settlement in millimeters if the preconsolidation pressure is 93 KPa. Use Cs = 1/7Cc.arrow_forwardrefer to the figure below. Determine the average stress increase in the clay layer below the center of the foundation due to the net foundation load of 50 tons.arrow_forwardA rectangular concrete slab, 3mx4m, rests on the surface of a soil layer as shown in the figure. The saturated clay has over consolidation ratio of 2, w=38%, and Cr=0.05. Determine the primary consolidation settlement of the clay. The load on the foundation is 2000OKN. Assume that 20% of voids in sand is air and porosity of sand is 0.43. Cc=0.28 Gs=2.65 4 m Fine sand 5 m Clay 2 marrow_forward
- The results of a consolidated undrained test, in which o3 = 392 kN/m?, on a normally consolidated clay are given as: Axial strain (%) Ao(kN/m²) ug(kN/m²) 0.5 0.75 156 196 226 235 250 245 240 235 99 120 132 147 161 170 173 175 1.3 2 3 4 4.5 Draw the K; line in a P' versus q' diagram. Also draw the s tress path for this test in the diagram.arrow_forwardThe soil profile shown in Figure 4.2 is subjected to the uniformly distributed load, Ao, on the ground surface. Given Ao = 15 kN/m2; H1 = 2 m; H2 = 3.5 m; and H3 = 5 m. Soil characteristics are as follows: *Sand: ya = 16.5 kN/ms; ysat = 19 kN/m3 *Clay: ysat = 18 kN/m:; LL = 31 %; e = 0.65; Cs = (1/5) C. Use: Ce= 0.009( LL – 10) a. Estimate the primary consolidation settlement in the clay (in mm.) if: The preconsolidation pressure, oc= 621 kN/m2 b. Estimate the value of the void ratio at the end of the primary consolidation which will be used for the analysis of the secondary consolidation Aar O Sand Clayarrow_forwardProblem No. 1 A circular foundation 2 m in diameter is shown in Figure. A normally consolidated clay layer 5 m thick is located below the foundation. Determine the primary consolidation settlement of the clay. 1m Circular foundation diameter, B= 2 m 10.5 m 0,5 m q=150 kN/m² ↓ Sand G.W.T. Y=17 kN/m³ Sand Ysat = 19 kN/m³ Normally consolidated clay H₁=5 m Ysat 18.5 kN/m³ Ce=0.16 €0=0.85arrow_forward
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