Question 2 A transistor is used as a switch and the waveforms are shown in Figure 2. The parameters are Vcc = 225 V, VBE(sat) = 3 V, IB = 8 A, VCE(sat) = 2 V, Ics = 90 A, td = 0.5 µs, tr = 1 µs, ts = 3 µs, tƒ = 2 μs, and f 10 kHz. The duty cycle is k 50%. The collector- emitter leakage current is ICEO = 2 mA. Determine the power loss due to the collector current: = = = (a) during turn-on ton = td + tr VCE Vcc (b) during conduction period tn V CE(sat) 0 toff" ton Ics 0.9 Ics (c) during turn-off toff = ts + tf (d) during off-time tot (e) the total average power losses PT ICEO 0 IBS 0 Figure 2 V BE(sat) 0 主 * td tr In Is If to iB VBE T= 1/fs

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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Question 2
A transistor is used as a switch and the waveforms are shown in Figure 2. The parameters are
Vcc = 225 V, VBE(sat) = 3 V, IB = 8 A, VCE(sat) = 2 V, Ics = 90 A, td = 0.5 µs, tr = 1 µs, ts = 3 µs, tƒ
= 2 μs, and f
10 kHz. The duty cycle is k 50%. The collector- emitter leakage current is
ICEO = 2 mA. Determine the power loss due to the collector current:
=
=
=
(a) during turn-on ton = td + tr
VCE
Vcc
(b) during conduction period tn
V CE(sat)
0
toff"
ton
Ics
0.9 Ics
(c) during turn-off toff = ts + tf
(d) during off-time tot
(e) the total average power losses PT
ICEO
0
IBS
0
Figure 2
V BE(sat)
0
主
*
td
tr
In
Is
If
to
iB
VBE
T= 1/fs
Transcribed Image Text:Question 2 A transistor is used as a switch and the waveforms are shown in Figure 2. The parameters are Vcc = 225 V, VBE(sat) = 3 V, IB = 8 A, VCE(sat) = 2 V, Ics = 90 A, td = 0.5 µs, tr = 1 µs, ts = 3 µs, tƒ = 2 μs, and f 10 kHz. The duty cycle is k 50%. The collector- emitter leakage current is ICEO = 2 mA. Determine the power loss due to the collector current: = = = (a) during turn-on ton = td + tr VCE Vcc (b) during conduction period tn V CE(sat) 0 toff" ton Ics 0.9 Ics (c) during turn-off toff = ts + tf (d) during off-time tot (e) the total average power losses PT ICEO 0 IBS 0 Figure 2 V BE(sat) 0 主 * td tr In Is If to iB VBE T= 1/fs
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