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Q7. For the following loop, assume the loop executes many iterations (the branch is almost always taken). What would be the steady state CPI of this code (e.g., assume branch always taken)? Assume the 5-stage MIPS pipeline, no branch delay slot in the ISA, branches resolved in the ID stage, and "predict branch not taken" strategy with one instruction squashed on a mispredict. loop: add R4, R6, R8 subi R2, R2, #8 lw R8, 1000 (R4) add R9, R8, R7 bne R2, R4, loop

Q7. For the following loop, assume the loop executes many iterations (the branch is almost always taken). What would be the steady state CPI of this code (e.g., assume branch always taken)? Assume the 5-stage MIPS pipeline, no branch delay slot in the ISA, branches resolved in the ID stage, and "predict branch not taken" strategy with one instruction squashed on a mispredict. loop: add R4, R6, R8 subi R2, R2, #8 lw R8, 1000 (R4) add R9, R8, R7 bne R2, R4, loop

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Q7. For the following loop, assume the loop executes many iterations (the branch is almost always taken). What would be the steady state CPI of this code (e.g., assume branch always taken)? Assume the 5-stage MIPS pipeline, no branch delay slot in the ISA, branches resolved in the ID stage, and "predict branch not taken" strategy with one instruction squashed on a mispredict. loop: add R4, R6, R8 subi R2, R2, #8 lw R8, 1000 (R4) add R9, R8, R7 bne R2, R4, loop
Transcribed Image Text:Q7. For the following loop, assume the loop executes many iterations (the branch is almost always taken). What would be the steady state CPI of this code (e.g., assume branch always taken)? Assume the 5-stage MIPS pipeline, no branch delay slot in the ISA, branches resolved in the ID stage, and "predict branch not taken" strategy with one instruction squashed on a mispredict. loop: add R4, R6, R8 subi R2, R2, #8 lw R8, 1000 (R4) add R9, R8, R7 bne R2, R4, loop
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