Q-Construction of a new building founded on a clayey soil was completed in January 2010. In January 2014, the average consolidation settlement of the foundation in clay was recorded as 10 mm. The ultimate consolidation settlement was estimated in design as 40 mm. Considering double drainage to occur at the clayey soil site, find the expected consolidation settlement in January 2019.

Q-Construction of a new building founded on a clayey soil was completed in January 2010. In January 2014, the average consolidation settlement of the foundation in clay was recorded as 10 mm. The ultimate consolidation settlement was estimated in design as 40 mm. Considering double drainage to occur at the clayey soil site, find the expected consolidation settlement in January 2019.

Principles of Foundation Engineering (MindTap Course List)

8th Edition

ISBN:9781305081550

Author:Braja M. Das

Publisher:Braja M. Das

Chapter2: Geotechnical Properties Of Soil

Section: Chapter Questions

Problem 2.19P

See similar textbooks

Similar questions

The soil profile shown is to carry a surcharge of 61 kPa applied at the ground surface. The result of the laboratory consolidation test of the middle of the clay layer is also shown. Calculate the settlement in the field caused by primary consolidation due to surcharge. The saturated unit weight of the clay is 18.2 kN/cum with a void ratio of 1.1. Please answer this asap. For upvote. Thank you very much
‹ample 9.1: Following results were recorded from a consolidation test on a specime turated clay, each load being maintained constant for 24 hours before the addition o ext increment.
Define the term critical void ratio.
please help me... If a soil sample tested in a direct shear box of 60 mm by 60 mm and the maximum readings for normal loads of 0.3, 0.5 and 1.0kN were 202, 265 and 511 kN, determine the strength parameters corresponding to effective stress. Please find: 1) UU test; Unconsolidated Untrained (Q-test or quick test) 2) CD test; Consolidated Drained ( S-test or slow test) 3) CU test; Consolidated Untrained (R-test) 4) UC test; Unconfined Compression (σ_3=0) Thank you..
Q11 Please provide justified answer asap to get a upvote
Figure 1 office illustrates the soil profile at a site for a proposed building. It is expected that the vertical stress at the middle of the clay layer will increase by 32 kPa. Calculate the final consolidation settlement. Ground water level is at the top of the clay layer. An oedometer test on a sample of the clay revealed that 90% consolidation on a 20-mm thick sample occurred in 40 minutes. The sample was drained on the upper and lower boundaries. Estimate the consolidation settlement in one year. Gs(clay) = 2.70 and Gs(sand) = 2.60. 5 m w = 23% Sand S = 90% w = 40% 10 m C= 0.3 OCR = 1 Clay Impervious rock Figure 1 0.9 U. avg 0.00 0.000 0.8 0.0 0.1 0.0 0.008 0.031 0.071 0.05 0.252 0.10 0.357 0.197 0.500 0.7 02 0.3 0.20 0.30 0.40 0.504 0.6 04 0.126 0.613 0.698 0.764 0.816 0.856 0.887 0.848 0.900 0.912 0.931 0.980 0.5 0.197 0.5 0.6 0.287 0.50 0.7 0.403 0.60 0.4 0.567 0.70 0.848 0.95 1.163 0,9 0.80 0.3 1.0 0.90 02 1.00 1.50 2.00 0.1 0.994 02 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 Time factor, T…
Solve asap. Thank You
None
R is 100
A consolidated drained tri-axial test was conducted on a normally consolidated day. The results were as foHows: 03 = 300 kPa (confining pressure) Deviators stress = 300 kPa o Compute the angle of shearing resistance. e Compute the angle that the failure plane makes with the major principal. stress. Compute the shear stress on the failure plane.
Calculate the primary consolidation settlement of the 8 ft thick clay layer (See Figure) that will result from the load taken by a 5 ft square footing. The clay is preconsolidated. waterproof rock
4. (a) Time required for a 3m clay layer, sitting on bedrock, and overlain by a sand layer to fully consolidate is 4 years. What if the clay layer was on a sand layer or another stiff clay layer? Please explain (with reasoning) how the time required for the consolidation process to complete is likely to be affected in either case (no calculations required to be shown).