A consolidated drained tri-axial test was conducted on a normally consolidatedday. The results were as foHows:03 = 300 kPa (confining pressure)Deviators stress = 300 kPao Compute the angle of shearing resistance.e Compute the angle that the failure plane makes with the major principal.stress.Compute the shear stress on the failure plane.

Answered: A consolidated drained tri-axial test…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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1. Test A set of 4-in diameter direct shear tests were conducted on a lightly cemented sand. Test results are as shown. Plot the data (units = psf) and determine c' (in psf) and '. How would c' change if there were no cementation? Number 1 2 3 Forces At Failure Normal (lb) 60 120 180 Shearing (lb) 40 71 108 Shear Stresses at Failure Normal (psf) Shearing (psf) 688 458 1375 814 2063 1238 c' = c' = 29.5 degrees 57.3 psf 0.4 psi
Below are results from three unconsolidated undrained triaxial tests performed on a fully saturated clay specimen: Test No. 1 2 Minor principal stress (psi) Major principal stress at failure (psi) 10 25 33 22 37 45 Moisture content = 21 % Determine: a) Void ratio (e) of the soil. You may use eS = wG_ (assume Gs = 2.70) %3D b) Deviatory stress at failure for each test trial c) Shear strength parameters (cu and ø). Hint: Sketch the Mohr's circles for the three trials. 3.
A series of unconsolidated undrained (UU) triaxial compression tests have been performed on two "identical" clay specimens. The test results are as follows: Test Number Confining Pressure (kPa)| Deviator Stress at Failure (kPa) 102 96 (i) (ii) 1 2 50 100 Plot the total stress Mohr circles for both specimens at failure (indicate the major and minor principal stresses on the plot). Draw the total stress Mohr-Coulomb failure envelop (i.e., the "p=0" envelop). Estimate the undrained shear strength.
Assume that both a triaxial shear test and a direct shear test are to be performed on a sample of dry sand. When the triaxial shear test is performed, the specimen fails when the major and minor principal stresses are 80 and 20 lbs/in^2, respectively. When the direct shear test is performed, what shear strength can be expected if the normal stress is 4000 lbs/ft^2?
A consolidated-drained tri-axial test was conducted on a normally consolidated clay. The results are as follows: O3 = 150 kN/m? (Aoa)f= 130 kN/m? Determine a. Angle of friction, o' b. Angle 0 that the failure plane makes with the major principal plane c. Find the normal stress o' and the shear stress tf on the failure plane d. Determine the effective normal stress on the plane of maximum shear stress
4/2 Determine the force in each member of the loaded truss. A 30⁰ 60° k B 400 kg
Q: A consolidated-drained tri-axial test was conducted on a normally consolidated clay. The results are as following: confining stress, G3 = 150 kN/m² and deviator stress, (Aod)t = 150 kN/m². i) Determine angle of friction, q; ii) Determine angle 0 that the failure plane makes with the major principal plane; iii) Find the normal stress and the shear stress ty on the failure plane; and iv) Determine the effective normal stress on the plane of maximum shear stress. Express your results in two decimal places.

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