Problem Statement = You install a heat pump to heat a cottage during the winter using the outside air as the heat source. You wish to maintain the interior temperature of the cottage at 22°C. A simplified model of the heat loss through the walls indicates that heat will need to be supplied at a rate of 0.14(Tinterior - Texterior) where Q is the rate at which heat must be supplied to the cottage (in kW), Tinterior is the interior air temperature (in C), and Texterior is the exterior air temperature (in C). You have a 1kW electric motor available to run the heat pump. What is the coldest winter day when the heat pump will be able to keep up to the heating demand? Answer Table Stage Description Your Answer Correct Answer * Due Date Grade (%) Part Weight Attempt Action/Message. Type 1 Coldest outdoor temperature (°C) Nov 7, 2024 11:59 pm 0.0 1 1/5 Submit * Correct answers will only show after due date has passed.

Problem Statement = You install a heat pump to heat a cottage during the winter using the outside air as the heat source. You wish to maintain the interior temperature of the cottage at 22°C. A simplified model of the heat loss through the walls indicates that heat will need to be supplied at a rate of 0.14(Tinterior - Texterior) where Q is the rate at which heat must be supplied to the cottage (in kW), Tinterior is the interior air temperature (in C), and Texterior is the exterior air temperature (in C). You have a 1kW electric motor available to run the heat pump. What is the coldest winter day when the heat pump will be able to keep up to the heating demand? Answer Table Stage Description Your Answer Correct Answer * Due Date Grade (%) Part Weight Attempt Action/Message. Type 1 Coldest outdoor temperature (°C) Nov 7, 2024 11:59 pm 0.0 1 1/5 Submit * Correct answers will only show after due date has passed.

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)

8th Edition

ISBN:9781305387102

Author:Kreith, Frank; Manglik, Raj M.

Publisher:Kreith, Frank; Manglik, Raj M.

Chapter1: Basic Modes Of Heat Transfer

Section: Chapter Questions

Problem 1.74P: A manufacturer in the United States wants to sell a refrigeration system to a customer in Germany....

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Part 1: Do the Analysis of the Ocean Thermal Gradient Power Plant shown below. Your Analysis will be easier to do in EES but it is up to you. Your EES program must be well documented and documentation in your code should reference system sketches. (The cycle and individual components) These sketches are done on attached engineering or typing paper, unless you are able to draw them in EES. You must validate your results with hand calculations on engineering paper that invoke the 1 and 2 Law from the perspective of the entire cycle, not the individual components. Of course, a system sketch is required. nd 1. An ocean thermal gradient power plant using a simple non-ideal Rankine Cycle operates with a peak boiler temperature of 70 °F and a condenser temperature of 40 °F. The warm surface water of the ocean is supplying the thermal energy to the boiler. Assume a high source temperature of 80 °F. The cooler water deeper in the ocean is the sink for heat rejection at the condenser. Assume a…
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The left side of this equation tells how much energy Q the cylinder gives to the water while it cools. The right side of this equation tells how much energy Q the water and aluminum cup absorb from the cylinder to warm up. Because it is the same energy, they are equal. What is known in this equation? Mcyl 411.7 g, malum 46.5 g, malum+water = 175 g Can you find: mwater =? g Twater = Talum = 20°C (water and cup of room temperature) 90°C, T; = 35°C (hot cylinder and cool "cylinder+cup+water" temperatures) Tcyl kCal Calum = 0.22, Cwater 1 (specific heat of water and aluminum, measured in units kg-°C What are we looking for is Ccul - How we find it? Plug all the numbers into the equation (1), Ccul will be one unknown which you can calculate from the equation. Important, convert all the masses from grams to kilograms! After you find Ccyl, compare it to known value for the copper 0.093(our cylinder is made out of copper). |Ceyl -0.093| % : · 100% 0.093
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