problem 4 A gaseous pollutant ROH in the air can photolyze in sunlight, shown as ROH + hv →R+OH (A<300 nm) Given the absorption cross section and the intensity of sunlight under a certain circumstance shown in the below table, the quantum yield for the light that can initiate the photolysis is 1.0 molecules/photon. Please estimate how long it takes for 10 mg/L ROH reduced to be 0.5 mg/L? Wavelength (nm) 200-225 225-250 250-275 275-300 300-325 325-350 Absorption cross section a (cm²/molecule) 0.2×10-19 0.9×10-19 2.0×10-19 1.3x10-19 1.5×10-19 1.6×10-19 Intensity of sunlight F(photons cm 2-¹) 0.3×10¹4 4.0×10¹4 2.0×10¹4 1.5×10¹4 0.8×10¹4 2.0×10¹4

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problem 4
A gaseous pollutant ROH in the air can photolyze in sunlight, shown as
ROH+ hv→ R+ OH (2<300 nm)
Given the absorption cross section and the intensity of sunlight under a certain
circumstance shown in the below table, the quantum yield for the light that can initiate
the photolysis is 1.0 molecules/photon. Please estimate how long it takes for
10 mg/L ROH reduced to be 0.5 mg/L?
Wavelength (nm)
200-225
225-250
250-275
275-300
300-325
325-350
Absorption cross section
a (cm²/molecule)
0.2×10-19
0.9×10-19
2.0×10-19
1.3×10-19
1.5×10-19
1.6×10-19
Intensity of sunlight
F(photons cm 2s-¹)
0.3×10¹4
4.0×1014
2.0×10¹4
1.5×1014
0.8×10¹4
2.0×10¹4
Transcribed Image Text:problem 4 A gaseous pollutant ROH in the air can photolyze in sunlight, shown as ROH+ hv→ R+ OH (2<300 nm) Given the absorption cross section and the intensity of sunlight under a certain circumstance shown in the below table, the quantum yield for the light that can initiate the photolysis is 1.0 molecules/photon. Please estimate how long it takes for 10 mg/L ROH reduced to be 0.5 mg/L? Wavelength (nm) 200-225 225-250 250-275 275-300 300-325 325-350 Absorption cross section a (cm²/molecule) 0.2×10-19 0.9×10-19 2.0×10-19 1.3×10-19 1.5×10-19 1.6×10-19 Intensity of sunlight F(photons cm 2s-¹) 0.3×10¹4 4.0×1014 2.0×10¹4 1.5×1014 0.8×10¹4 2.0×10¹4
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