[Review Topics] [References] CHEMWORK The thiosulfate ion (S,032-) is oxidized by iodine as follows: 25,032 (aq) + I2(aq) → S4062 (aq) + 21"(aq) In a certain experiment, 7.82×10-3 mol/L of S,032- is consumed in the first 11.0 seconds of the reaction. Calculate the rate of production of iodide ion. mol/L/s Submit Hide Hints Hint 1 Hint 2 The rate of production is the amount (mol/L) produced per unit time (seconds in this case).

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Chapter1: Chemical Foundations
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[Review Topics]
[References]
CHEMWORK
The thiosulfate ion (S2032-) is oxidized by iodine as follows:
25,032 (aq) + I2(aq) → S406² (aq) + 21°(aq)
In a certain experiment, 7.82x10-3 mol/L of S,032- is consumed in the first 11.0 seconds of the reaction.
Calculate the rate of production of iodide ion.
mol/L/s
Submit
Hide Hints
Hint 1
Hint 2
The rate of production is the amount (mol/L) produced per unit time (seconds in this case).
Transcribed Image Text:[Review Topics] [References] CHEMWORK The thiosulfate ion (S2032-) is oxidized by iodine as follows: 25,032 (aq) + I2(aq) → S406² (aq) + 21°(aq) In a certain experiment, 7.82x10-3 mol/L of S,032- is consumed in the first 11.0 seconds of the reaction. Calculate the rate of production of iodide ion. mol/L/s Submit Hide Hints Hint 1 Hint 2 The rate of production is the amount (mol/L) produced per unit time (seconds in this case).
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