Consider the balanced chemical reaction below. Calculate the percent yield for the reaction.. MnO2 + 4HCI → MnCl2 + Cl2 + 2H,0 2 NEXT > The reaction was started with 1.00 mol of MnO, and 95.0 g of HCI (MW 36.458 g/mol). Set up the table below that represents 100% yield with the given reaction conditions. Ignore the water side product. MnO2 4HCI MnCl2 Cl2 Before (mol) Change (mol) After (mol) 2 RESET 1.00 95.0 -95.0 2.61 -2.61 0.625 -0.625 0.375 -0.375 4.00 -4.00

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Question 22 of 22
Consider the balanced chemical reaction below. Calculate the percent yield for
the reaction...
MnO, + 4HCI → MnCl2 + Cl2 + 2H,0
2
NEXT >
The reaction was started with 1.00 mol of MnO, and 95.0 g of HCI (MW 36.458 g/mol). Set up
the table below that represents 100% yield with the given reaction conditions. Ignore the
water side product.
MnO2
4HCI
->
MnCl2
Cl2
Before (mol)
Change (mol)
After (mol)
2 RESET
1.00
95.0
-95.0
2.61
-2.61
0.625
-0.625
0.375
-0.375
4.00
-4.00
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Transcribed Image Text:5:38 PM Tue Nov 9 * 100 Question 22 of 22 Consider the balanced chemical reaction below. Calculate the percent yield for the reaction... MnO, + 4HCI → MnCl2 + Cl2 + 2H,0 2 NEXT > The reaction was started with 1.00 mol of MnO, and 95.0 g of HCI (MW 36.458 g/mol). Set up the table below that represents 100% yield with the given reaction conditions. Ignore the water side product. MnO2 4HCI -> MnCl2 Cl2 Before (mol) Change (mol) After (mol) 2 RESET 1.00 95.0 -95.0 2.61 -2.61 0.625 -0.625 0.375 -0.375 4.00 -4.00 Tap here or pull up for additional resources
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