Ideal Stoichiometry Percent Yield 1. Aluminum reacts with excess Copper (II) Sulfate. Al (s) + CuSO, (aq) →→___Al₂(SO₂), (aq) +_____ Cu (s) a. If 1.85 g of Al reacts with an excess of CuSO, and the percentage yield of Cu is 56.6%, what mass of Cu is produced? 2. Methanol can be produced through the following reaction. CO (g) + H₂(g) →→ CH₂OH (1) a. If 75 g of CO reacts with an excess of H, to produce 68.4 g of CH,OH, what is the percentage yield of CH,OH?

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Please answer these two questions they're 2 parts to one question but please solve them separate. Thanks, and please show work, make sure to balance the equations, etc. 

**Ideal Stoichiometry Percent Yield**

**1. Aluminum reacts with excess Copper (II) Sulfate.**

___ Al (s) + ___ CuSO₄ (aq) → ___ Al₂(SO₄)₃ (aq) + ___ Cu (s)

a. If 1.85 g of Al reacts with an excess of CuSO₄, and the percentage yield of Cu is 56.6%, what mass of Cu is produced?

**2. Methanol can be produced through the following reaction.**

___ CO (g) + ___ H₂ (g) → ___ CH₃OH (l)

a. If 75 g of CO reacts with an excess of H₂ to produce 68.4 g of CH₃OH, what is the percentage yield of CH₃OH?

---

*Important Constants and Formulas:*

- **Left over** = initial – consumed
- **% Yield** = (Actual/Theoretical) * 100
- **Avogadro’s number:** 6.023 * 10²³ molecules/1 mol
- **STP Volume:** 1 mol/22.4 L
Transcribed Image Text:**Ideal Stoichiometry Percent Yield** **1. Aluminum reacts with excess Copper (II) Sulfate.** ___ Al (s) + ___ CuSO₄ (aq) → ___ Al₂(SO₄)₃ (aq) + ___ Cu (s) a. If 1.85 g of Al reacts with an excess of CuSO₄, and the percentage yield of Cu is 56.6%, what mass of Cu is produced? **2. Methanol can be produced through the following reaction.** ___ CO (g) + ___ H₂ (g) → ___ CH₃OH (l) a. If 75 g of CO reacts with an excess of H₂ to produce 68.4 g of CH₃OH, what is the percentage yield of CH₃OH? --- *Important Constants and Formulas:* - **Left over** = initial – consumed - **% Yield** = (Actual/Theoretical) * 100 - **Avogadro’s number:** 6.023 * 10²³ molecules/1 mol - **STP Volume:** 1 mol/22.4 L
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