Try Another Version Submit Answer 3 item attempts remaining A chemist wants to prepare 0.740 M HCI, Commercial hydrochloric acid is 12.4 M. How many milliliters of the commercial acid does the chemist require to make up 1.40 L of the dilute acid? [References]

Steps and explanation please.

Question 4

Calculate Average molarity (M) of Acetic acid in vinegar, using the following data. Calculate the mass percent of acetic acid in vinegar, using your average Acetic acid concentration (M) from above result. Table 2. Data for titration of 20.00 mL of vinegar with approximately 1.2 M NaOH. Note you must use the exact concentration of the standard NaOH solution to calculate the moles of NaOH.

Both questions please!! Show work

show full and complete procedure HANDWRITTEN only. Please answer a) and b), note they are subparts of question 1.

II Calculating molarity using solute moles A chemist prepares a solution of iron(II) bromide (FeBr,) by measuring out 152. umol of iron(II) bromide into a 200. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's iron(II) bromide solution. Round your answer to 3 significant digits. mol Explanation Check O 2020 McGraw-Hill Education. All Rights Reserved. Terms of Use | Privacy l Accessi Type here to search 番 き

Data Table Final buret reading Initial buret reading Volume used Sample 1 Vinegar Base Vinegar Sample 2 Sample 3 (if needed) Base Vinegar Base JOML Som 0,05 110mL/802 10ML 884 JUML 0.00 10μL OML Tome 0.00 10mL 80.2 mL 10ML 88mL come some *If a pipet is used to measure the volume of vinegar, record only in the space for volume used. Molarity of base (NaOH) 1685 M Vinegar number N/A CALCULATIONS: In the spaces below, show calculation setups for Sample 1 only. Show answers for both samples in the boxes. 1. Moles of base (NaOH) 2. Moles of acid (HC2H3O2) used to neutralize (react with) the above number of moles of base 3. Molarity of acetic acid in the vinegar Sample 1 Sample 2 Sample 3 (if needed) 4. Average molarity of acetic acid in the vinegar 5. Grams of acetic acid per liter (from average molarity) 6. Mass percent acetic acid in vinegar sample (density of vinegar = 1.005 g/mL) - 252 -

CHEMISTRY (Please write the complete solution legibly. No long explanation needed. Answer in 2 decimal places. Box the fin al answer.) 125 mL of 12.0 M HCl solution is diluted with water to a final volume of 1.00 L. What is themolarity of the diluted solution? (Answer: 1.50 M)

Thanks in advanced, these are just 4 step problems but this one has me stumped for some reason. Use to being given grams. Zinc metal reacts with hydrochloric acid ( Zn + 2HCl --> ZnCl^2 + H^2 ) You add .156 mole of hydrochloric acid solution to .145 mole of zinc in a beaker and waited several minutes for the reaction to complete. How many moles of ZnCl^2 was produced and what was the limiting reagent, Zn or HCl?