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15. How much water (in mL) must be added to 200 mL of a 1.25 M soldium chloride (NaCl) solution to decrease its concentration to 0.770 M? (answer; 125 mL)

15. How much water (in mL) must be added to 200 mL of a 1.25 M soldium chloride (NaCl) solution to decrease its concentration to 0.770 M? (answer; 125 mL)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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For question 15 I am certain I have the correct answer after using the V1C1=V2C2 formula but it’s not matching the key. Could you let me know if I’m correct or incorrect?
250 ant 3.09 - 7.39 %3D 100mt Imol 7.5g. 22moles 34.02 Vi 15. How much water (in mL) must be added to 200 mL of a 1.25 M soldium chloride (NaCl) solution to decrease its concentration to 0.770 M? (answer; 125 mL) Ca Vi Ci= Vgx C2 200mレ×1.25N-Va x679014 325ML -> 0.7770M 0,77014 16. What is the molarity fo a solution prepared by diluting 225 mL of 2.00 M nitric acid solution to a final volume of 275 mL? (answer: 1.64 M) Hints for assigned chapter 13 problems
Transcribed Image Text:250 ant 3.09 - 7.39 %3D 100mt Imol 7.5g. 22moles 34.02 Vi 15. How much water (in mL) must be added to 200 mL of a 1.25 M soldium chloride (NaCl) solution to decrease its concentration to 0.770 M? (answer; 125 mL) Ca Vi Ci= Vgx C2 200mレ×1.25N-Va x679014 325ML -> 0.7770M 0,77014 16. What is the molarity fo a solution prepared by diluting 225 mL of 2.00 M nitric acid solution to a final volume of 275 mL? (answer: 1.64 M) Hints for assigned chapter 13 problems
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