is positive in this this in Cu reaction explain why 2n(s) |2n+2 || C₁²² | Cu Does it gain electrons from C4+27

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
icon
Concept explainers
Question
**Electrochemical Cells and Reactions**

In this section, we will explore a question related to electrochemical cells and the behavior of copper (Cu) in a specific reaction.

**Question (3):**
"Cu is positive in this reaction. Explain why in this reaction?"

The reaction provided is:
\[ \text{Zn(s)} | \text{Zn}^{2+} || \text{Cu}^{2+} | \text{Cu} \]

In the diagram above, an electrochemical cell is represented, consisting of zinc (Zn) and copper (Cu) electrodes. The notation suggests that the cell involves a zinc electrode in solid form (Zn(s)) and a copper electrode in solid form (Cu), each immersed in their respective ionic solutions — zinc ions (\(\text{Zn}^{2+}\)) and copper ions (\(\text{Cu}^{2+}\)). The double vertical lines (||) in the cell notation represent the salt bridge or membrane separating the two half-cells.

The question hints at understanding why copper (Cu) is considered positive in this cell reaction and asks whether it gains electrons from \(\text{Cu}^{2+}\), which has a 2+ charge.

Here’s an explanation:

In an electrochemical cell, each half-cell reaction facilitates either oxidation or reduction. Typically, Zinc (Zn) undergoes oxidation (loses electrons), while Copper (Cu) undergoes reduction (gains electrons).

### Half-Reactions:

**Oxidation Half-Reaction (at anode):**
\[ \text{Zn(s)} → \text{Zn}^{2+} (aq) + 2e^- \]

**Reduction Half-Reaction (at cathode):**
\[ \text{Cu}^{2+} (aq) + 2e^- → \text{Cu(s)} \]

In this setup:

1. **Oxidation Occurs at Zinc Electrode (Anode):** 
   Zinc metal (Zn(s)) loses electrons (is oxidized) to form \(\text{Zn}^{2+}\) ions.
   
2. **Reduction Occurs at Copper Electrode (Cathode):** 
   Copper ions (\(\text{Cu}^{2+}\)) in the solution gain electrons (are reduced) to form copper metal (Cu).

As a result of these half-reactions, zinc acts as the anode (negative electrode), and copper acts as the cathode (positive electrode).
Transcribed Image Text:**Electrochemical Cells and Reactions** In this section, we will explore a question related to electrochemical cells and the behavior of copper (Cu) in a specific reaction. **Question (3):** "Cu is positive in this reaction. Explain why in this reaction?" The reaction provided is: \[ \text{Zn(s)} | \text{Zn}^{2+} || \text{Cu}^{2+} | \text{Cu} \] In the diagram above, an electrochemical cell is represented, consisting of zinc (Zn) and copper (Cu) electrodes. The notation suggests that the cell involves a zinc electrode in solid form (Zn(s)) and a copper electrode in solid form (Cu), each immersed in their respective ionic solutions — zinc ions (\(\text{Zn}^{2+}\)) and copper ions (\(\text{Cu}^{2+}\)). The double vertical lines (||) in the cell notation represent the salt bridge or membrane separating the two half-cells. The question hints at understanding why copper (Cu) is considered positive in this cell reaction and asks whether it gains electrons from \(\text{Cu}^{2+}\), which has a 2+ charge. Here’s an explanation: In an electrochemical cell, each half-cell reaction facilitates either oxidation or reduction. Typically, Zinc (Zn) undergoes oxidation (loses electrons), while Copper (Cu) undergoes reduction (gains electrons). ### Half-Reactions: **Oxidation Half-Reaction (at anode):** \[ \text{Zn(s)} → \text{Zn}^{2+} (aq) + 2e^- \] **Reduction Half-Reaction (at cathode):** \[ \text{Cu}^{2+} (aq) + 2e^- → \text{Cu(s)} \] In this setup: 1. **Oxidation Occurs at Zinc Electrode (Anode):** Zinc metal (Zn(s)) loses electrons (is oxidized) to form \(\text{Zn}^{2+}\) ions. 2. **Reduction Occurs at Copper Electrode (Cathode):** Copper ions (\(\text{Cu}^{2+}\)) in the solution gain electrons (are reduced) to form copper metal (Cu). As a result of these half-reactions, zinc acts as the anode (negative electrode), and copper acts as the cathode (positive electrode).
Expert Solution
steps

Step by step

Solved in 3 steps with 4 images

Blurred answer
Knowledge Booster
Thermochemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY