is positive in this this in Cu reaction explain why 2n(s) |2n+2 || C₁²² | Cu Does it gain electrons from C4+27

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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**Electrochemical Cells and Reactions**

In this section, we will explore a question related to electrochemical cells and the behavior of copper (Cu) in a specific reaction.

**Question (3):**
"Cu is positive in this reaction. Explain why in this reaction?"

The reaction provided is:
\[ \text{Zn(s)} | \text{Zn}^{2+} || \text{Cu}^{2+} | \text{Cu} \]

In the diagram above, an electrochemical cell is represented, consisting of zinc (Zn) and copper (Cu) electrodes. The notation suggests that the cell involves a zinc electrode in solid form (Zn(s)) and a copper electrode in solid form (Cu), each immersed in their respective ionic solutions — zinc ions (\(\text{Zn}^{2+}\)) and copper ions (\(\text{Cu}^{2+}\)). The double vertical lines (||) in the cell notation represent the salt bridge or membrane separating the two half-cells.

The question hints at understanding why copper (Cu) is considered positive in this cell reaction and asks whether it gains electrons from \(\text{Cu}^{2+}\), which has a 2+ charge.

Here’s an explanation:

In an electrochemical cell, each half-cell reaction facilitates either oxidation or reduction. Typically, Zinc (Zn) undergoes oxidation (loses electrons), while Copper (Cu) undergoes reduction (gains electrons).

### Half-Reactions:

**Oxidation Half-Reaction (at anode):**
\[ \text{Zn(s)} → \text{Zn}^{2+} (aq) + 2e^- \]

**Reduction Half-Reaction (at cathode):**
\[ \text{Cu}^{2+} (aq) + 2e^- → \text{Cu(s)} \]

In this setup:

1. **Oxidation Occurs at Zinc Electrode (Anode):** 
   Zinc metal (Zn(s)) loses electrons (is oxidized) to form \(\text{Zn}^{2+}\) ions.
   
2. **Reduction Occurs at Copper Electrode (Cathode):** 
   Copper ions (\(\text{Cu}^{2+}\)) in the solution gain electrons (are reduced) to form copper metal (Cu).

As a result of these half-reactions, zinc acts as the anode (negative electrode), and copper acts as the cathode (positive electrode).
Transcribed Image Text:**Electrochemical Cells and Reactions** In this section, we will explore a question related to electrochemical cells and the behavior of copper (Cu) in a specific reaction. **Question (3):** "Cu is positive in this reaction. Explain why in this reaction?" The reaction provided is: \[ \text{Zn(s)} | \text{Zn}^{2+} || \text{Cu}^{2+} | \text{Cu} \] In the diagram above, an electrochemical cell is represented, consisting of zinc (Zn) and copper (Cu) electrodes. The notation suggests that the cell involves a zinc electrode in solid form (Zn(s)) and a copper electrode in solid form (Cu), each immersed in their respective ionic solutions — zinc ions (\(\text{Zn}^{2+}\)) and copper ions (\(\text{Cu}^{2+}\)). The double vertical lines (||) in the cell notation represent the salt bridge or membrane separating the two half-cells. The question hints at understanding why copper (Cu) is considered positive in this cell reaction and asks whether it gains electrons from \(\text{Cu}^{2+}\), which has a 2+ charge. Here’s an explanation: In an electrochemical cell, each half-cell reaction facilitates either oxidation or reduction. Typically, Zinc (Zn) undergoes oxidation (loses electrons), while Copper (Cu) undergoes reduction (gains electrons). ### Half-Reactions: **Oxidation Half-Reaction (at anode):** \[ \text{Zn(s)} → \text{Zn}^{2+} (aq) + 2e^- \] **Reduction Half-Reaction (at cathode):** \[ \text{Cu}^{2+} (aq) + 2e^- → \text{Cu(s)} \] In this setup: 1. **Oxidation Occurs at Zinc Electrode (Anode):** Zinc metal (Zn(s)) loses electrons (is oxidized) to form \(\text{Zn}^{2+}\) ions. 2. **Reduction Occurs at Copper Electrode (Cathode):** Copper ions (\(\text{Cu}^{2+}\)) in the solution gain electrons (are reduced) to form copper metal (Cu). As a result of these half-reactions, zinc acts as the anode (negative electrode), and copper acts as the cathode (positive electrode).
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