Problem 2Consider the following feedback control system.(i)(ii)K(s+2)s(s + 1)(s+3)5+65+7Use Routh-Hurwitz criterion to find the range of K for which the closed-loop systemis stable.Using the Routh table from part (a), find the range of K for which the closed-loopsystem will have one pole in the ORHP and rest of the poles in the OLHP. This impliesthere will be only one sign changes in the 1st column.

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Answered: Problem 2 Consider the following…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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3. Can a series connection of two BIBO unstable systems ever be BIBO stable? What about a parallel connection and a negative feedback connection? Explain. Hint: Think pole-zero cancellation.
For the following feedback control systems: a. Sketch its Root Locus b. Show clearly, with arrows, the direction the closed-loop poles are moving as K goes from 0 to ∞ c. Find the Asymptotes (intersection and angles), and show them on the Root Locus d. Indicate on the Root Locus the Break-in and Break-away points C(s) R(s) + E(s) K s2 +17s + 70 s2-6s+8 1 S+5 4
Hello Sir.Good Evening. I have a question in my home work related Control System Lesson. The following below is my question.Please advise, Thank you so much.
For a negative unity feedback system. R(s) + where G(s) 5+1 s²+45+5 the poies of the closed loop system are QA1 and 4 B. None DC 2 and 3 OD A Of 1 and 4 E(s) G(s) C(s)
Aunity feedback system has the following open-loop poles: -2+j1, -2-j1, -0.2. The angle of departure from the complex pole is calculated as Answer:
What is positive feedback system?
Consider the following control system: R |Ke s+1 + or- What is the unit-step response for negative feedback, withc = 1.0? This is one out of five questions on the same control system. A C() = 0.5(1 -e") B C() = 0.5(1-e*) C() = 1- e- D C) = 1-e05t
QUESTION 3 Consider a unity negative feedback control system. Assume that the plant G(s) does not have an integrator and you are using a proportional compensator K. You want to increase the closed-loop step tracking performance. Currently, the steady- state tracking error of the closed-loop system with K=K_old to a unit step signal is 0.1. You would like this error to be reduced to 0.02 with a new proportional compensator K=K_new. How does the proportional gain have to change to make this possible? We assume that the closed-loop is stable for all values of the proportional gain. Do not guess as incorrect answers will incur a penalty. K_new = 6.33 K_old K_new = 5.44 K_old K_new = 5 K_old K_new = 4.66 K_old
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Please help with this question will upvote step by step clear and neat explaination
The block diagram representation of a tachometer feedback speed control system is shown in Figure 4. R(s) + 15.5 C(s) s+1 Tachometer Ko Figure 4 (i). Develop the closed loop transfer function. (ii). Evaluate the value of DC gain K and the time constant T with the assumption of tachometer feedback variable Ko. (ii). The system step response is represented by y = K(1 – e), sketch the step response curve for the system when the tachometer feedback variable Ko. (iv). Write a general MATLAB codes to reduce the block diagram into a single feedback control system, to calculate transfer function and to obtain unit step response and impulse response. (v). Comment on the step response curve which is obtained in (i) and (iv) with respect to K and time constant T. ko=2 k1=2.2 Note: Refer the Table for Ko and K, values.
Consider the feedback system below for which we intend to study both the stability and the steady-state properties. R(s) + 50 C(s) 2 s+1 a) Represent the system in a standard unity-feedback control structure and using any forms of your choice, construct a state-space representation of the closed-loop system. b) Using Routh-Hurtwitz criterion or any other means determine if the closed-loop system is stable or not. Specify the number of poles on the left-half s-plane, on the right-half s-plane and on the j w-axis.

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