• We will use the Wattmeter to find the average power supplied/absorbed by each component. The following figure shows how to connect the Wattmeter to measure the average power absorbed by the resistor. Note that the Wattmeter consists of a Voltmeter and an Ammeter. The Voltmeter must be connected in parallel with the component and the Ammeter must be connected in series with the component. You must pay attention to the polarity of the voltage across the component as well as the direction of the current flowing through the component. 5Vpk 1kHz 30° ww 40 Z=A-JB Wattmeter-XWM1 2.503 W Power factor: 1.00000 Voltage Current • • Similarly connect a second Wattmeter to measure the average power supplied by the source. Connect a third Wattmeter to measure the average power in the capacitor. Does this value agree with the theoretical value? Perform Interactive Simulation under Analysis and Simulation. Double click on Wattmeters to see the average power values. Note that the Wattmeter also measures the power factor. Include the schematic and Wattmeter outputs in your report. 2) Find the average power delivered by the ideal current source and the average power absorbed by the resistors in the following circuit if ig = 30 cos 25000t mA. 202 w 50 w 40 μF 40 uH Answer: P(current source) = 990 µW, P(22) = 900 µW, P(52) = 90 μW
• We will use the Wattmeter to find the average power supplied/absorbed by each component. The following figure shows how to connect the Wattmeter to measure the average power absorbed by the resistor. Note that the Wattmeter consists of a Voltmeter and an Ammeter. The Voltmeter must be connected in parallel with the component and the Ammeter must be connected in series with the component. You must pay attention to the polarity of the voltage across the component as well as the direction of the current flowing through the component. 5Vpk 1kHz 30° ww 40 Z=A-JB Wattmeter-XWM1 2.503 W Power factor: 1.00000 Voltage Current • • Similarly connect a second Wattmeter to measure the average power supplied by the source. Connect a third Wattmeter to measure the average power in the capacitor. Does this value agree with the theoretical value? Perform Interactive Simulation under Analysis and Simulation. Double click on Wattmeters to see the average power values. Note that the Wattmeter also measures the power factor. Include the schematic and Wattmeter outputs in your report. 2) Find the average power delivered by the ideal current source and the average power absorbed by the resistors in the following circuit if ig = 30 cos 25000t mA. 202 w 50 w 40 μF 40 uH Answer: P(current source) = 990 µW, P(22) = 900 µW, P(52) = 90 μW
Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter23: Resistive-inductive-capacitive Series Circuits
Section: Chapter Questions
Problem 9RQ: What is the power factor of the circuit in Question 6?
Related questions
Question
Answer question 2 using Multisim please

Transcribed Image Text:• We will use the Wattmeter to find the average power supplied/absorbed by each component.
The following figure shows how to connect the Wattmeter to measure the average power
absorbed by the resistor. Note that the Wattmeter consists of a Voltmeter and an Ammeter. The
Voltmeter must be connected in parallel with the component and the Ammeter must be connected
in series with the component. You must pay attention to the polarity of the voltage across the
component as well as the direction of the current flowing through the component.
5Vpk
1kHz
30°
ww
40
Z=A-JB
Wattmeter-XWM1
2.503 W
Power factor:
1.00000
Voltage
Current
•
•
Similarly connect a second Wattmeter to measure the average power supplied by the source.
Connect a third Wattmeter to measure the average power in the capacitor. Does this value agree
with the theoretical value?
Perform Interactive Simulation under Analysis and Simulation. Double click on Wattmeters to
see the average power values. Note that the Wattmeter also measures the power factor.
Include the schematic and Wattmeter outputs in your report.

Transcribed Image Text:2) Find the average power delivered by the ideal current source and the average power absorbed by the
resistors in the following circuit if ig = 30 cos 25000t mA.
202
w
50
w
40 μF
40 uH
Answer: P(current source) = 990 µW, P(22) = 900 µW, P(52) = 90 μW
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