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a) Write down the order of the transfer function in each of the following cases. Assume that there are no terms in the numerator that will cancel terms in the denominator. 10 H(s) H(s) = s+1 5 (s+3)(s—. 4) 4s1 5 H(s) = H(s) - 83 +1 s27s 6 H(s) H(s) = s(s²+4s) 2s27s+1 84583882 +3s+2 H(s) 83 +8 s+1 = H(s) s34s26s+5 s52s4383 + 4s2 +5s +6 Note: You might want to do the last question first because the last question asks you to write some python code to calculate the zeros and poles. You could use that code here to help you (except the first problem which you should be able to do by inspection alone) Find the poles and zeros for each of the following transfer functions 1. S+3 H(s) = 8 5 2. H(s): = s238 +1 s2 +48 +3 3. s(s+4) H(s) s3+2s23s 4. 82-586 H(s) = - 8382-68 5. H(s): = s2 +48 +3 s45836s2 - 6

a) Write down the order of the transfer function in each of the following cases. Assume that there are no terms in the numerator that will cancel terms in the denominator. 10 H(s) H(s) = s+1 5 (s+3)(s—. 4) 4s1 5 H(s) = H(s) - 83 +1 s27s 6 H(s) H(s) = s(s²+4s) 2s27s+1 84583882 +3s+2 H(s) 83 +8 s+1 = H(s) s34s26s+5 s52s4383 + 4s2 +5s +6 Note: You might want to do the last question first because the last question asks you to write some python code to calculate the zeros and poles. You could use that code here to help you (except the first problem which you should be able to do by inspection alone) Find the poles and zeros for each of the following transfer functions 1. S+3 H(s) = 8 5 2. H(s): = s238 +1 s2 +48 +3 3. s(s+4) H(s) s3+2s23s 4. 82-586 H(s) = - 8382-68 5. H(s): = s2 +48 +3 s45836s2 - 6

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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a) Write down the order of the transfer function in each of the following cases. Assume that there are no terms in the numerator that will cancel terms in the denominator. 10 H(s) H(s) = s+1 5 (s+3)(s—. 4) 4s1 5 H(s) = H(s) - 83 +1 s27s 6 H(s) H(s) = s(s²+4s) 2s27s+1 84583882 +3s+2 H(s) 83 +8 s+1 = H(s) s34s26s+5 s52s4383 + 4s2 +5s +6
Transcribed Image Text:a) Write down the order of the transfer function in each of the following cases. Assume that there are no terms in the numerator that will cancel terms in the denominator. 10 H(s) H(s) = s+1 5 (s+3)(s—. 4) 4s1 5 H(s) = H(s) - 83 +1 s27s 6 H(s) H(s) = s(s²+4s) 2s27s+1 84583882 +3s+2 H(s) 83 +8 s+1 = H(s) s34s26s+5 s52s4383 + 4s2 +5s +6
Note: You might want to do the last question first because the last question asks you to write some python code to calculate the zeros and poles. You could use that code here to help you (except the first problem which you should be able to do by inspection alone) Find the poles and zeros for each of the following transfer functions 1. S+3 H(s) = 8 5 2. H(s): = s238 +1 s2 +48 +3 3. s(s+4) H(s) s3+2s23s 4. 82-586 H(s) = - 8382-68 5. H(s): = s2 +48 +3 s45836s2 - 6
Transcribed Image Text:Note: You might want to do the last question first because the last question asks you to write some python code to calculate the zeros and poles. You could use that code here to help you (except the first problem which you should be able to do by inspection alone) Find the poles and zeros for each of the following transfer functions 1. S+3 H(s) = 8 5 2. H(s): = s238 +1 s2 +48 +3 3. s(s+4) H(s) s3+2s23s 4. 82-586 H(s) = - 8382-68 5. H(s): = s2 +48 +3 s45836s2 - 6
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