14 V 1492 www Problem 6: Find the Thevenin and Norton equivalents at terminals a-b of the circuit shown below. 1 A ww 602 3 A ww 502 a ob
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- Find the Norton equivalent of the source circuit to the left of the load in Figure. Treat load as short- circuit wire for analysis. 2 A ic 60 N 15 N + 40 V ia iB Load V 180 NDetermine the Thevenin's equivalent circuit across points A and B by disconnecting the 25-ohm resistor. Find the current through the 25-ohm resistor. R1 RS Sohm 25ohm R3 V2 V1 75ohm SOV 30V R2 10ohm O VTH - 2125 V. RTH 941 ohms, IL- G489 A O VTH - 41.25 V RTH - 9 375 ohms, IL - 0.489 A O VTH = 35 V RTH12.5 ohms, IL-0.9333 A VTH 4125 V RTH 9:375 ohms. L-0427 A VTH4125 V RTH H 641 ohms IL=0489 A B.I need help with both parts please. Here is the question. Determine the Thevenin Equivalent circuit looking into the terminals a and b. Use the principle of superposition to find the open circuit voltage Voc=Vab. Do not use mesh or nodal analysis. a) Determine the equivalent impedance looking into the terminals a and b. Please put in numeric value. b) Determine the open-circuit voltage. Please put a numeric value.
- Customer Prob 4 10 Given step-down transformer T1 has N1/N2 = 10 and vab = 170COS(377t) a) Find is(t). b) Find customer's uncorrected (PF). N2 is N1 T1 26.5mH Utility TL Vab Utility Power Plant -Using nodal analysis, kindly solve for V1 and V2. Provide complete solution.R₁ =1292 Igc = 0.16A IDC = Problem #21) Determine the source current Ipc and the resistor voltage V4 as shown in the following circuit using the Reduce and Return Method if the source voltage is Vpc = 72 volts. R₂=402 R₁ =1552 R₁=4592 0.16 IDC =. V₁=. 2 (A) 36 (A) (V)
- 4. For the circuit shown in Figure, use Node analysis to find the voltages V₁ and V₂. 540° A L 18 C TH -160 V₂ www R₁ 120 HIP R₂ w 100 V₂ 15/0° VCircuits Find vth rth and a b power maximum?6 Let Vab_c be the voltage when R21 is connected and Vab_d when RL21 is disconnected, find these peak voltages and current flow through R21. Express your result as IR21=900mA, Vab_c=5.3V, Vab_d=2.8V R20 6Q V6 8V a bl R21 3Ω R22 m 4Ω R23 20