PROBLEM 1O1: A continuous strip footing is to be located concentrically under a 300 mm wall that delivers service loads D = 360 kN/m and L= 220 kN/m to the top of the footing. The bottom of the footing will be 1.2 m below the fina ground surface. The soil has a density of 20Kn/m3 and allowable bearing capacity of 280 Kn/m2. Materials strengths are f =21 MPa and fy 276 MPa. Find: a. The required width of footing, b. The required effective and total depths, based on shear, c. The required flexural steel area. d. Give an on-scale schematic structural detail. ***Use 20 mm Ø
PROBLEM 1O1: A continuous strip footing is to be located concentrically under a 300 mm wall that delivers service loads D = 360 kN/m and L= 220 kN/m to the top of the footing. The bottom of the footing will be 1.2 m below the fina ground surface. The soil has a density of 20Kn/m3 and allowable bearing capacity of 280 Kn/m2. Materials strengths are f =21 MPa and fy 276 MPa. Find: a. The required width of footing, b. The required effective and total depths, based on shear, c. The required flexural steel area. d. Give an on-scale schematic structural detail. ***Use 20 mm Ø
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:CE ELECT 1S- Foundation and Retaining Wall Design
PLATE 101
PROBLEM I01:
A continuous strip footing is to be located concentrically under a 300 mm wall that delivers service loads
D = 360 kN/m and L= 220 kN/m to the top of the footing. The bottom of the footing will be 1.2 m below the final
ground surface. The soil has a density of 20Kn/m3 and allowable bearing capacity of 280 Kn/m?. Materials
strengths are fe =21 MPa and fy = 276 MPa. Find:
%3D
a. The required width of footing,
b. The required effective and total depths, based on shear,
The required flexural steel area.
d. Give an on-scale schematic structural detail.
С.
***Use 20 mm Ø
PROBLEM IO2:
Referring to problem 101, design the footing considering the moments induce by the following loads given below
in addition to the service loads:
MD = 50 Kn-m
Use the following load combinations:
U= 1.2D + 1.6L
U = 1.2DL + 1.OL + 1.0E
ML = 60 Kn-m
ME = 36 Kn-M
%3D
a. The required width of footing,
b. The required effective and total depths, based on shear,
The required flexural steel area.
d. Give an on-scale schematic structural detail.
***Use 20 mm Ø
C.
2021/09/08 7:22
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