A strip footing is to be placed 2m below the surface or soil having a cohesion of 40 KPa, unit weight of 18.2 KN/m', and angle of friction of 10° Ne = 8.02 N = 1.94 Nc = 9.61 N = 2.69 N, = 0.56 N,' = 0.24 a) Assuming local shear failure, compute the ultimate bearing capacity of the footing if the width is 1.25 m. Ans. 287.21 KPa b) Considering a rectangular footing of 1.25m x 6m and a load factor of 2.5, determine the allowable bearing capacity under general shear failure. B. Qut = cN: (1+ 03) +yD,Ng + 0.5YBN,(1 – 0.2 %3D Ans. 204.97 KPa c) Find the allowable load that the rectangular footing could carry Ans. 1537.28 KN

A strip footing is to be placed 2m below the surface or soil having a cohesion of 40 KPa, unit weight of 18.2 KN/m', and angle of friction of 10° Ne = 8.02 N = 1.94 Nc = 9.61 N = 2.69 N, = 0.56 N,' = 0.24 a) Assuming local shear failure, compute the ultimate bearing capacity of the footing if the width is 1.25 m. Ans. 287.21 KPa b) Considering a rectangular footing of 1.25m x 6m and a load factor of 2.5, determine the allowable bearing capacity under general shear failure. B. Qut = cN: (1+ 03) +yD,Ng + 0.5YBN,(1 – 0.2 %3D Ans. 204.97 KPa c) Find the allowable load that the rectangular footing could carry Ans. 1537.28 KN

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter16: Shallow Foundations-bearing Capacity

Section: Chapter Questions

Problem 16.19CTP: A 2.0 m 2.0 m square pad footing will be placed in a normally consolidated clay soil to carry a...

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