Peak Q1. For a half-wave rectifier show that the average diode current is given by Dav = IL (L+π √2 VP ) Vr Q2. For the full-wave peak rectifier Show that the maximum diode current is given by Dmax = 1₂ (1+2π √ Up 2 Vr
Peak Q1. For a half-wave rectifier show that the average diode current is given by Dav = IL (L+π √2 VP ) Vr Q2. For the full-wave peak rectifier Show that the maximum diode current is given by Dmax = 1₂ (1+2π √ Up 2 Vr
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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can you proof these 2 questions handwritten(I dont want to book proofs or internet proof I don't understand them because of that I am asking you) step by step detailed solution thank you
![Peak
Q1. For a half-wave rectifier show
that the average
diode current is
given by
Dav = IL (L+π √2 VP )
Vr
Q2. For the full-wave peak rectifier
Show that the maximum diode
current is given by
Dmax = 1₂ (1+2π
√ Up
2 Vr](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff48ed50b-2b46-4ef7-b41f-f3bbfb8360e1%2F40bd4129-d292-4bc2-8287-4a64426a7c31%2Fn6yr4h_processed.png&w=3840&q=75)
Transcribed Image Text:Peak
Q1. For a half-wave rectifier show
that the average
diode current is
given by
Dav = IL (L+π √2 VP )
Vr
Q2. For the full-wave peak rectifier
Show that the maximum diode
current is given by
Dmax = 1₂ (1+2π
√ Up
2 Vr
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