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Part A Assuming complete dissociation of the solute, how many grams of KNO3 must be added to 275 mL of water to produce a solution that freezes at -14.5 C? The freezing point for pure water is 0.0°C and Kţ is equal to 1.86°C/m. Express your answer to three significant figures and include the appropriate units. > View Available Hint(s) HA Value

Part A Assuming complete dissociation of the solute, how many grams of KNO3 must be added to 275 mL of water to produce a solution that freezes at -14.5 C? The freezing point for pure water is 0.0°C and Kţ is equal to 1.86°C/m. Express your answer to three significant figures and include the appropriate units. > View Available Hint(s) HA Value

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I Review | Constants | Periodic Table Colligative properties are those that depend on the number of solute particles. Because electrolytes dissociate into ions, the concentration of particles in the solution is greater than the formula-unit concentration of the solution. For example, if 1 mol of NazSO, totally dissociates, 3 mol of ions are produced (2 mol of Nat ions and1 mol of SO,?- ions). Thus, a colligative property such as osmotic pressure will be three times greater for a 1 M NazSO, solution than for a 1 M nonelectrolyte solution. Part A Assuming complete dissociation of the solute, how many grams of KNO3 must be added to 275 mL of water to produce a solution that freezes at -14.5°C? The freezing point for pure water is 0.0 °C and Kf is equal to 1.86 °C/m. Express your answer to three significant figures and include the appropriate units. > View Available Hint(s) However, complete dissociation of electrolytes does not always occur. The extent of dissociation is expressed by the van't Hoff factor, i: HA moles of particles in solution moles of solute dissolved Value 2 = The equations for colligative properties can be written to include i, For example, Submit AT = K - m i ATb = Kb m-i Part B Complete previous partís)
Transcribed Image Text:I Review | Constants | Periodic Table Colligative properties are those that depend on the number of solute particles. Because electrolytes dissociate into ions, the concentration of particles in the solution is greater than the formula-unit concentration of the solution. For example, if 1 mol of NazSO, totally dissociates, 3 mol of ions are produced (2 mol of Nat ions and1 mol of SO,?- ions). Thus, a colligative property such as osmotic pressure will be three times greater for a 1 M NazSO, solution than for a 1 M nonelectrolyte solution. Part A Assuming complete dissociation of the solute, how many grams of KNO3 must be added to 275 mL of water to produce a solution that freezes at -14.5°C? The freezing point for pure water is 0.0 °C and Kf is equal to 1.86 °C/m. Express your answer to three significant figures and include the appropriate units. > View Available Hint(s) However, complete dissociation of electrolytes does not always occur. The extent of dissociation is expressed by the van't Hoff factor, i: HA moles of particles in solution moles of solute dissolved Value 2 = The equations for colligative properties can be written to include i, For example, Submit AT = K - m i ATb = Kb m-i Part B Complete previous partís)
Expert Solution
Step 1

Given data:

  •  275 mL of water 
  • Freezing point of solution is -14.5oC
  • Kf = 1.86oC/m
  • Freezing point of pure water = 0oC
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