Can you explain why this expression ends up like this? |H(jw)| ==1ωRC22√√ (πtc - w² ) ² + ( x + c ) ²LC1(RC)√1+ (~RC--(D))"12 V{(s)RwZog(s)1/sCSL V₂(s)

Answered: |H(jw)| = = 1 ω RC 2 2 √√ (πtc - w² ) ²…

Engineering

Electrical Engineering

|H(jw)| = = 1 ω RC 2 2 √√ (πtc - w² ) ² + ( x + c ) ² LC 1 (RC) √1+ (~RC--(D))" 1 2 V{(s) R w Zog(s) 1/sC SL V₂(s)

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

Can you explain why this expression ends up like this?

|H(jw)| =
=
1
ω
RC
2
2
√√ (πtc - w² ) ² + ( x + c ) ²
LC
1
(RC)
√1+ (~RC--(D))"
1
2

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